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irinina [24]
3 years ago
7

Graph each equation y=7x-7

= 7x - 7" align="absmiddle" class="latex-formula">
how can you graph this
Mathematics
1 answer:
Dafna1 [17]3 years ago
6 0

to graph a LINEar equation, since it's just a straight line, recall, to draw a straight line all you need is two points.

so we can just pick two random "x" values, hmmmmm say x = 0, what's "y"?

y = 7(0)-7 => y = -7....................................... so that gives us the point (0, -7)

hmmm x = 2, what is "y"?

y = 7(2) - 7 => y = 14-7 => y = 7................. so we get the point (2, 7).

then just plot those, and run a line through them.

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Express x^2-5x+8 in the form (x-a)^2+b where a and b are top-heavy fractions
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Step-by-step explanation:

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P(x) with rational coefficients has the given roots (i and 7 + 8i) Find two additional roots?
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Which is a possible turning point for the continuous
kvasek [131]

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3 years ago
5. A company sells small, colored binder clips in packages of 20 and offers a money-back guarantee if two or more of the clips a
SOVA2 [1]

Answer:

a) Binomial.

b) n=20, p=0.01, k≥2

The probability hat a package sold will be refunded is P=0.0169.

Step-by-step explanation:

a) We know that

  • the defective probability is constant and independent.
  • the sample size is bigger than one subject.

The most appropiate distribution to represent this random variable is the binomial.

b) The parameters are:

  • Sample size (amount of clips in the package): n=20
  • Probability of defective clips: p=0.01.
  • number of defective clips that trigger the money-back guarantee: k≥2

The probability of the package being refunded can be calculated as:

P(x\geq2)=1-(P(x=0)+P(x=1))\\\\\\P(x=k) = \dbinom{n}{k} p^{k}q^{n-k}\\\\\\P(x=0) = \dbinom{20}{0} p^{0}q^{20}=1*1*0.8179=0.8179\\\\\\P(x=1) = \dbinom{20}{1} p^{1}q^{19}=20*0.01*0.8262=0.1652\\\\\\P(x\geq2)=1-(0.8179+0.1652)=1-0.9831=0.0169

6 0
3 years ago
WILL GIVE BRAINLIEST TO PERSON WHO ANSWERS
Tpy6a [65]
A² - 225 = (a-15)(a+15)
..................................................................
7 0
3 years ago
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