The slope of y = 3x - 4 on the interval [2, 5] is 3 and the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
<h3>How to determine the slope?</h3>
The interval is given as:
x = 2 to x = 5
The slope is calculated as:
<u>16. y = 3x - 4</u>
Substitute 2 and 5 for x
y = 3*2 - 4 = 2
y = 3*5 - 4 = 11
So, we have:
Divide
m = 3
Hence, the slope of y = 3x - 4 on the interval [2, 5] is 3
<u>17. y = 2x^2-4x - 2</u>
Substitute 2 and 5 for x
y = 2 * 2^2 - 4 * 2 - 2 = -2
y = 2 * 5^2 - 4 * 5 - 2 = 28
So, we have:
Divide
m = 10
Hence, the slope of y = 2x^2-4x - 2 on the interval [2, 5] is 10
Read more about slopes at:
brainly.com/question/3605446
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Answer: Roughly 111.97
Step-by-step explanation:
1. 39 divided by 3 is 13.
2. 4367 divided by 3 is not evenly distributed. Rounding, it would work out to be roughly 1455.66
3. 1455.66 divided by 13 is roughly 111.97 (Again, this does not distribute evenly)
4. To check your work, multiply 111.97 times 13 and you should get somewhere around 1455.66 which is (4367 divided by 3).
Hopefully this helps! Feel free to mark brainliest! :)
The answer would be -0.102564 repeating because if you do the math before dividing you would get -8/6.5/-1.5/-8
Answer:
y = 2x + 6 and 2y-4x=12 are the same line, so have infinitely many solutions.
Step-by-step explanation:
2y - 4x = 12
This is the same as y = 2x + 6
Answer:
F
Step-by-step explanation:
