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Kitty [74]
3 years ago
8

Which is the value of 3b² — b when b = 5?

Mathematics
1 answer:
yanalaym [24]3 years ago
3 0

Answer:

The answer is

<h2>70</h2>

Step-by-step explanation:

3b² - b

when b = 5

Substitute the value of b that's 5 into the expression

That's

3(5)² - 5

= 3(25) - 5

= 75 - 5

We have the final answer as

<h3>70</h3>

Hope this helps you

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Write these price increases in order from greatest to least<br> 2/3, 75%, 7 / 10, 62.5%, 0.5
In-s [12.5K]

Answer:

75, 7/10, 2/3, 62,5, .5

Step-by-step explanation:

75%=75%

7/10=70%

2/3=66.67%

62.5%=62.5%

.5=50%

5 0
3 years ago
What is the solution of the equation?
nadya68 [22]

Answer:

q = 4

Fully simplifying this equation gives you answer (A) q = 4

Hope this helps!

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ANYBODY WHO ANSWERS THIS QUESTION CORRECTLY WILL GET 40 POINTS. THE ONES IN GREY ARE THE ANSWER OPTIONS.
masya89 [10]

Answer:

140 students are in the school

Step-by-step explanation:

According to the Pie Chart, 70 students are 50%. So then, you multiply 50% of the survey to get 100% (the entirety surveyed). So 70 x 2 = 140

So there were 140 students in the school.

7 0
3 years ago
Read 2 more answers
The difference of a number c and 17 is more than 33​
serg [7]

Answer:

c > 50

Step-by-step explanation:

c -17 > 33 \\ c -17 +17 > 33 +17 \\ c > 50

4 0
3 years ago
Determine whether the set of all linear combinations of the following set of vector in R^3 is a line or a plane or all of R^3.a.
Temka [501]

Answer:

a. Line

b. Plane

c. All of R^3

Step-by-step explanation:

In order to answer this question, we need to study the linear independence between the vectors :

1 - A set of three linearly independent vectors in R^3 generates R^3.

2 - A set of two linearly independent vectors in R^3 generates a plane.

3 - A set of one vector in R^3 generates a line.

The next step to answer this question is to analyze the independence between the vectors of each set. We can do this by putting the vectors into the row of a R^(3x3) matrix. Then, by working out with the matrix we will find how many linearly independent vectors the set has :

a. Let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}-2&5&-3\\6&-15&9\\-10&25&-15\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix  ⇒

\left[\begin{array}{ccc}-2&5&-3\\0&0&0\\0&0&0\end{array}\right]

We find that the second vector is a linear combination from the first and the third one (in fact, the second vector is the first vector multiply by -3).

We also find that the third vector is a linear combination from the first and the second one (in fact, the third vector is the first vector multiply by 5).

At the end, we only have one vector in R^3 ⇒ The set of all linear combinations of the set a. is a line in R^3.

b. Again, let's put the vectors into the rows of a matrix :

\left[\begin{array}{ccc}1&2&0\\1&1&1\\4&5&3\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&1\\0&1&-1\\0&0&0\end{array}\right]

We find that there are only two linearly independent vectors in the set so the set of all linear combinations of the set b. is a plane (in fact, the third vector is equivalent to the first vector plus three times the second vector).

c. Finally :

\left[\begin{array}{ccc}0&0&3\\0&1&2\\1&1&0\end{array}\right] ⇒ Applying matrix operations we find that the matrix is equivalent to this another matrix ⇒

\left[\begin{array}{ccc}1&1&0\\0&1&2\\0&0&3\end{array}\right]

The set is linearly independent so the set of all linear combination of the set c. is all of R^3.

4 0
3 years ago
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