Answer:
x=7
Step-by-step explanation:
Multiply the numerator of the first fraction by the denominator of the second fraction. Set this equal to the product of the denominator of the first fraction and the numerator of the second fraction.
2(x+13)=(x−2)⋅8
Solve the equation for x.
Simplify 2(x+13).
Start simplifying.
0+0+2(x+13)=(x−2)⋅8
Simplify by adding zeros.
2(x+13)=(x−2)⋅8
Apply the distributive property.
2x+2⋅13=(x−2)⋅8
Multiply 2 by 13
2x+26=(x−2)⋅8
Simplify (x−2)⋅8
Apply the distributive property.
2x+26=x⋅8−2⋅8
Simplify the expression.
Move 8 to the left of x
2x+26=8⋅x−2⋅8
Multiply −2 by 8
2x+26=8x−16
Move all terms containing x to the left side of the equation.
Subtract 8x from both sides of the equation
2x+26−8x=−16
Subtract 8x from 2x
−6x+26=−16
Move all terms not containing x to the right side of the equation.
Subtract 26 from both sides of the equation
−6x=−16−26
Subtract 26 from −16
−6x=−42
Divide each term in −6x=−42 by −6 and simplify
Divide each term in −6x=−42 by −6
Simplify the left side
Cancel the common factor of −6.
Divide x by 1.
Simplify the right side.
Divide −42 by −6.
x=7
Answer with Step-by-step explanation:
We are given that u and v are functions of x and both are differentiable at x=0
a.We have to find the values of 
Using this formula
Then , we get
![[\frac{d(uv)}{dx}]_{x=0}=u'(0)v(0)+u(0)v'(0)=7(2)+4(1)=14+4=18](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28uv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3Du%27%280%29v%280%29%2Bu%280%29v%27%280%29%3D7%282%29%2B4%281%29%3D14%2B4%3D18)
![[\frac{d(uv)}{dx}]_{x=0}=18](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28uv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D18)
b.
![[\frac{d(u/v)}{dx}]_{x=0}=\frac{u'(0)v(0)-u(0)v'(0)}{v^2(0)}=\frac{7(2)-4(1)}{2^2}=\frac{14-4}{4}=\frac{10}{4}=\frac{5}{2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28u%2Fv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7Bu%27%280%29v%280%29-u%280%29v%27%280%29%7D%7Bv%5E2%280%29%7D%3D%5Cfrac%7B7%282%29-4%281%29%7D%7B2%5E2%7D%3D%5Cfrac%7B14-4%7D%7B4%7D%3D%5Cfrac%7B10%7D%7B4%7D%3D%5Cfrac%7B5%7D%7B2%7D)
![[\frac{d(u/v)}{dx}]_{x=0}=\frac{5}{2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28u%2Fv%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7B5%7D%7B2%7D)
c.
![[\frac{d(v/u)}{dx}]_{x=0}=\frac{v'(0)u(0)-v(0)u'(0)}{u^2(0)}=\frac{1(4)-7(2)}{4^2}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28v%2Fu%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7Bv%27%280%29u%280%29-v%280%29u%27%280%29%7D%7Bu%5E2%280%29%7D%3D%5Cfrac%7B1%284%29-7%282%29%7D%7B4%5E2%7D)
![[\frac{d(v/u)}{dx}]_{x=0}=\frac{-10}{16}=\frac{-5}{8}](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28v%2Fu%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D%5Cfrac%7B-10%7D%7B16%7D%3D%5Cfrac%7B-5%7D%7B8%7D)
d.
![[\frac{d(-6v-9u)}{dx}]_{x=0}=-6v'(0)-9u'(0)=-6(1)-9(7)=-6-63=-69](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28-6v-9u%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D-6v%27%280%29-9u%27%280%29%3D-6%281%29-9%287%29%3D-6-63%3D-69)
![[\frac{d(-6v-9u)}{dx}]_{x=0}=-69](https://tex.z-dn.net/?f=%5B%5Cfrac%7Bd%28-6v-9u%29%7D%7Bdx%7D%5D_%7Bx%3D0%7D%3D-69)
Answer:
The answer should be "Outlier".
Answer:
A single point and a line that extends forever in one direction
Step-by-step explanation:
Answer:
1. -10
2. -12x+8
Step-by-step explanation:
hope this helps :)
