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madam [21]
4 years ago
5

Can someone please help me on number 13

Mathematics
2 answers:
alexandr402 [8]4 years ago
5 0
Equation: w * 12 = 384  (* = Multiplication symbol)
Answer: 32 weeks

Work:

384 divided by 12 is 32. We can check this by multiplying $12 by the total of what we earned in 32 weeks which is 384.

32 * 12 = 384

Mazyrski [523]4 years ago
3 0
3W = 384 is the equation and W = 32
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What values do you need to know to create a box plot? Select all that apply.
Papessa [141]

Answer:

The values you need to know to create a box plot are:

lower quartile ⇒ 2nd

maximum value  ⇒ 3rd

median ⇒ 5th

Step-by-step explanation:

Box plots is a type of graph that can help to organize data.

To graph a box plot the following data points must be calculated:

  • The minimum value ⇒ least value
  • The first quartile ⇒ lower quartile (the middle of the data before the median)
  • The median ⇒ the middle value of the arranged data from smallest to greatest
  • The third quartile ⇒ upper quartile (the middle of the data after the median)
  • The maximum value ⇒ greatest value

After you make the box plot graph, you can display and compare distributions of data

Let us answer the question

The values you need to know to create a box plot are:

lower quartile ⇒ 2nd

maximum value  ⇒ 3rd

median ⇒ 5th

5 0
3 years ago
Read 2 more answers
If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple ar
sleet_krkn [62]

This question is incomplete, the complete question is;

If n is a positive integer, how many 5-tuples of integers from 1 through n can be formed in which the elements of the 5-tuple are written in increasing order but are not necessarily distinct.

In other words, how many 5-tuples of integers  ( h, i , j , m ), are there with  n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1 ?

Answer:

the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Step-by-step explanation:

Given the data in the question;

Any quintuple ( h, i , j , m ), with n ≥ h ≥ i ≥ j ≥ k ≥ m ≥ 1

this can be represented as a string of ( n-1 ) vertical bars and 5 crosses.

So the positions of the crosses will indicate which 5 integers from 1 to n are indicated in the n-tuple'

Hence, the number of such quintuple is the same as the number of strings of ( n-1 ) vertical bars and 5 crosses such as;

\left[\begin{array}{ccccc}5&+&n&-&1\\&&5\\\end{array}\right] = \left[\begin{array}{ccc}n&+&4\\&5&\\\end{array}\right]

= [( n + 4 )! ] / [ 5!( n + 4 - 5 )! ]

= [( n + 4 )!] / [ 5!( n-1 )! ]

= [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

Therefore, the number of 5-tuples of integers from 1 through n that can be formed is [ n( n+1 ) ( n+2 ) ( n+3 ) ( n+4 ) ] / 120

4 0
3 years ago
What is 4 to the 3rd power <br><br> what is 2 to the 6th power<br><br> 40 points btw
mezya [45]
4^3=4*4*4=64
2^6=2*2*2*2*2*2=64
3 0
3 years ago
Can you please help me with this question?​
LenKa [72]

Answer:

congruent segments

Step-by-step explanation:

9x+2=15x-52

6x = 50

x = 50/6

7 0
3 years ago
SOMEONE PLEASE JUST ANSWER THIS FOR BRAINLIEST!!!
AnnyKZ [126]

this is the answer I came up with hopes this helps

5 0
3 years ago
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