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BabaBlast [244]

3 years ago

5

−(7y+0.6)=3.6−y PLEASE ANSWER QUICKLY

1 answer:

ivanzaharov [21]3 years ago

7 0

Y= -1/2. final answer. Your welcome

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Find the area of the figure.<br><br>12 ft<br>18 ft<br>18 ft<br>36 ft

Nataly_w [17]

Answer:

139968

Step-by-step explanation:

Multiply the all of the numbers together and you have your answer (:

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3 years ago

Which is NOT true about a direct proportion?

Nina [5.8K]

Answer:

Because it is acorrding to question answer

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3 years ago

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3 years ago

The number of chocolate chips in a bag of chocolate chip cookies is approximately normally distributed with mean of 1262 and a s

Andrew [12]

Answer:

a) 1186

b) Between 1031 and 1493.

c) 160

Step-by-step explanation:

Normal Probability Distribution

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the z-score of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the p-value, we get the probability that the value of the measure is greater than X.

Normally distributed with mean of 1262 and a standard deviation of 118.

This means that $\mu = 1262, \sigma = 118$

a) Determine the 26th percentile for the number of chocolate chips in a bag. 

This is X when Z has a p-value of 0.26, so X when Z = -0.643.

$Z = \frac{X - \mu}{\sigma}$

$-0.643 = \frac{X - 1262}{118}$

$X - 1262 = -0.643*118$

$X = 1186$

(b) Determine the number of chocolate chips in a bag that make up the middle 95% of bags.

Between the 50 - (95/2) = 2.5th percentile and the 50 + (95/2) = 97.5th percentile.

2.5th percentile:

X when Z has a p-value of 0.025, so X when Z = -1.96.

$Z = \frac{X - \mu}{\sigma}$

$-1.96 = \frac{X - 1262}{118}$

$X - 1262 = -1.96*118$

$X = 1031$

97.5th percentile:

X when Z has a p-value of 0.975, so X when Z = 1.96.

$Z = \frac{X - \mu}{\sigma}$

$1.96 = \frac{X - 1262}{118}$

$X - 1262 = 1.96*118$

$X = 1493$

Between 1031 and 1493.

(c) What is the interquartile range of the number of chocolate chips in a bag of chocolate chip cookies?

Difference between the 75th percentile and the 25th percentile.

25th percentile:

X when Z has a p-value of 0.25, so X when Z = -0.675.

$Z = \frac{X - \mu}{\sigma}$

$-0.675 = \frac{X - 1262}{118}$

$X - 1262 = -0.675*118$

$X = 1182$

75th percentile:

X when Z has a p-value of 0.75, so X when Z = 0.675.

$Z = \frac{X - \mu}{\sigma}$

$0.675 = \frac{X - 1262}{118}$

$X - 1262 = 0.675*118$

$X = 1342$

IQR:

1342 - 1182 = 160

7 0

3 years ago

Which function is quadratic?

PilotLPTM [1.2K]

Answer:

step 1. A, B,D are incorrectly written as these are not all coordinates. they must be written (x, y)

step 2. so the question becomes is C a quadratic

step 3. The x values must be evenly spaced. the x values are evenly spaced by a difference of 4

step 4. write out the y values: -126, -14, 2, 18

step 5. write out the differences: 140, 16, 16

step 6. write out the differences: -124, 0.

step 7. after doing this twice the numbers nust be the same for this to be a quadratic which they aren't

step 8. C is not a quadratic.

8 0

3 years ago