The given statement is false because it isn't an empty set!
<u>Step-by-step explanation:</u>
We have following sets of inequalities:
From we get ,
Therefore solution set is x=2.
Now, for we get ,
Therefore solution set is x>2.
For we get ,
Therefore solution set is x<2.
Now, the union of x=2, x<2 & x>2 is -∞<x<∞. i.e. all possible values of x. And so above statement is false because it isn't an empty set!
Answer:
A.
Statement: ∠6 ≅ ∠14
Reason: For parallel lines cut by a transversal, corresponding angles are congruent.
Step-by-step explanation:
In the figure attached, a plot of the problem is shown.
Given p || q and r is a transversal which cut p and q, then ∠1 ≅ ∠5 and ∠2 ≅ ∠6.
Given r || s and q is a transversal which cut r and s, then ∠6 ≅ ∠14 and ∠8 ≅ ∠16.
From the picture we see that ∠1 and ∠2 are supplementary, that is, their addition is equal to 180º. ∠2 ≅ ∠6 and ∠6 ≅ ∠14, then ∠2 ≅ ∠14, in consequence ∠1 and ∠14 are supplementary.
Answer:
(5x+12) (5x-12)
Step-by-step explanation:
Use the difference of squares fromula.
Where a = 5x and b =12.