The legs of a triangle with a hypotenuse that measures 15 units long have lengths that are equal to 15 times the sine or cosine of the given angle.
leg 1 = (15 units) x (cos 19) = 14.18 units
leg 2 = (15 units) x (sin 19) = 4.88 units
The lengths of the legs are 14.18 units and 4.88 units.
Answer:
32cm and 28cm
Step-by-step explanation:
Area of a trapezium=0.5 ( sum of parallel sides ) × height
600=0.5( 4+a+a)×20
where a is the length of the shorter side
600÷0.5=(4+2a)×20
1200=(4+2a)×20
1200÷20=4+2a
60=4+2a
60-4=2a
56=2a
56÷2=a
28=a.
since the longer side is 4 cm more than th shorter side , 28 +4=32
Answer:
y = -2 x = 0
Step-by-step explanation:
1. 3x-4y = 8
2. 18-5y = 10
Multiply equation 1 by 6
3. 18x-24y = 48
Subtract equation 2 from equation 3
4. -19y = 38
y = 38/-19
y = -2
Sub y = -2 back into equation 1
3x-4(-2) = 8
3x + 8 = 8
3x = 0
x = 0/3
x = 0
Area = Length x Width
The Length is 2 inches
The Width is 5/6 inches
2 * (5/6) = 10/6
simplify and you get....
5/3
F(x)=x
Domain: 1 2 3 4 5 6
Range: 1 2 3 4 5 6
F(x)=2x
Domain: 1 2 3 4
Range: 0 2 4 6
