Answer:
cos x ≠ 0 ⇔ x ≠ ; k ∈ N
<=> cos²x + sin²x = 1
⇔ 1 = 1
=> x = { R \ (pi/2 + k.pi); k ∈ N}
Step-by-step explanation:
You are trying so solve
<span><span>3^x</span>=8</span>
and since 8 is not an integral power of x you need a calculator.
it is <span><span>ln(8)/</span><span>ln(3)</span></span>
or
<span><span><span>log(8)/</span><span>log(3)</span></span></span>
Note that √2 + √2 = 2√2
2/(2√2) = (√2)/2 = 0.707 (simplified)
0.707 is your answer
~
which one ?
the bottom or the top or is this a trick
Answer:
sorry dude I don't know so sorry