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2 years ago

12

True or False. The larger the distance between two adjacent numbers in the five‑number summary, the more spread out the data in

that interval.

1 answer:

Leona [35]2 years ago

4 0

Answer: Its True

Step-by-step explanation:

The statement is true because the Percentages are preferred and also they are easier to compare than counts.

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Which function do you evaluate first in g(f(x))? f(x) g(x) f(g(x))

Mazyrski [523]

For the composite function g(f(x)), the function f(x) goes first in terms of evaluation. This is the inner most function. You would read it from right to left in terms of determining the order of evaluation.

4 0

2 years ago

Read 2 more answers

klio [65]

Answer:

The probability that a student taking only math will get picked is approximately 29%

Step-by-step explanation: This is because out of the total number of students taking math (95), 52 of such students are also taking science. In order to get the number of students only taking math you have to do 95-52=43 and to put that against the amount of total students the ratio would be 43:147 or 42/147 and if you plug 42/147 into a calculator you will recieve a long decimal that you can then round to 29%.

6 0

2 years ago

Round 76070.7376413 to 2 decimal places

lakkis [162]

<h3>Answer:</h3><h2>76,070.74</h2><h3>Step-by-step explanation:</h3>

When you round decimals, your looking at the place value, then your looking at the place value next to it.

<u>If you see a number that is 0 - 4 behind the place value your rounding to, you do nothing to the place value.</u>

<u>If you see a number that is 5 - 9 behind the place value your rounding to, you add one to the place value.</u>

<h3><u>Example 1:</u></h3>

Round the Number 71.25 to the <u>Tenths place.</u>

<u>When we go to the place value, Tenths, we go behind the Tenths place value:</u>

71.<em>2</em><u>5</u>

<u>2 is the Tenths place value, 5 is the place value behind the Tenths place value.</u>

<u>Since 5 is able to be rounded up, you add one to the tenths place.</u>

<u>It should be rounded to 71.3. There cannot be numbers where you've rounded, just zeroes.</u>

<h3><u>Example 2:</u></h3>

Round the Number <u>3,345.8493</u> to the <u>Thousands place.</u>

3 is the Thousands place, 3 is the place value behind the Thousands place value.

3 is not in between 5 - 9. So, the rounded answer is 3,000.

When numbers behind the Place Value cannot round the Thousands place value, it turns into zeroes too.

Answer:

Round 76070.7376413 to the Hundredths place value.

The 3 is the Hundredths place value, the 7 is the place value behind the Hundredths place value.

7 qualifies for the numbers 5 - 9.

Therefore, you add 1 to the hundredths place value.

Your final answer is (76,070.74)

Best of Luck to you.

If you have any questions, feel free to comment below.

Merry Christmas!

8 0

3 years ago

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper

Korvikt [17]

Answer:

90.67% probability that John finds less than 7 golden sheets of paper

Step-by-step explanation:

For each container, there are only two possible outcomes. Either it contains a golden sheet of paper, or it does not. The probability of a container containing a golden sheet of paper is independent of other containers. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

At Munder Difflin Paper Company, the manager Mitchell Short randomly places golden sheets of paper inside of 30% of their paper containers.

This means that $p = 0.3$

14 of these containers of paper.

This means that $n = 14$

What is the probability that John finds less than 7 golden sheets of paper?

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6)$

In which

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 0) = C_{14,0}.(0.3)^{0}.(0.7)^{14} = 0.0068$

$P(X = 1) = C_{14,1}.(0.3)^{1}.(0.7)^{13} = 0.0407$

$P(X = 2) = C_{14,2}.(0.3)^{2}.(0.7)^{12} = 0.1134$

$P(X = 3) = C_{14,3}.(0.3)^{3}.(0.7)^{11} = 0.1943$

$P(X = 4) = C_{14,4}.(0.3)^{4}.(0.7)^{10} = 0.2290$

$P(X = 5) = C_{14,5}.(0.3)^{5}.(0.7)^{9} = 0.1963$

$P(X = 6) = C_{14,6}.(0.3)^{6}.(0.7)^{8} = 0.1262$

$P(X < 7) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3) + P(X = 4) + P(X = 5) + P(X = 6) = 0.0068 + 0.0407 + 0.1134 + 0.1943 + 0.2290 + 0.1963 + 0.1262 = 0.9067$

90.67% probability that John finds less than 7 golden sheets of paper

7 0

2 years ago

I will give a thanks 5 stars and i will give you the brainliest Gwen mows 1/4 acre in 3/4 hours. what fraction is used to find t

Vinil7 [7]

Answer:

D

Step-by-step explanation:

4 0

3 years ago