16 is $32
idk the others.... sorry.
Im mean I’d be down to help
Answer:
The answer is B.) 3
Step-by-step explanation:
Answer:
The other endpoint is located at (-4,-2)
Step-by-step explanation:
we know that
The diagonals of a rhombus bisect each other
That means-----> The diagonals of a rhombus intersect at the midpoint of each diagonal
so
The point (0,4) is the midpoint of the two diagonals
The formula to calculate the midpoint between two points is equal to

we have


substitute

<em>Find the x-coordinate
of the other endpoint</em>


<em>Find the y-coordinate
of the other endpoint</em>



therefore
The other endpoint is located at (-4,-2)
I find it convenient to look at the differences and the rate at which those differences are made up.
8. Jim is closing the $150 gap at the rate of $7.50 per week. He will catch up in
... 150/(7.5/week) = 20 weeks
9. At noon, the price of Stock A has increased by 0.05×3 = 0.15, so is now $15.90, which is $0.63 more than Stock B at that time. The prices are closing the gap at the rate of $0.05 +0.13 = $0.18 per hour, so will be the same after
... $0.63/($0.18/hour) = 3.5 hours . . . . after noon, at 3:30 pm
_____
You can also write and solve equations for the prices of the stocks. Or you can use a graphing calculator to tell you the solution. When equations are involved, I like to solve them the simplest possible way: let technology do it.
You are given the value at a time, and the rate of change of that value, so the equations are easily written in point-slope form. You will note that the common price at 3:30 pm (15.5 hours after midnight) is one that is not a whole number of cents. (That's usually OK for when trading stocks.)