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Mkey [24]
3 years ago
13

the backyard if a new home is shaped like a trapezoid with a height of 46 ft and bases of 73 ft and 114 ft. what is the cost of

putting sod on the gard, if the landscaper charge 23 cent per square foot for sod
Mathematics
1 answer:
Doss [256]3 years ago
4 0

Answer:

$989.23

Step-by-step explanation:

The cost will be the product of the area in square feet and the cost per square foot.

The area of a trapezoid is given by the formula ...

... A = (1/2)(b1 +b2)h . . . . . where b1 and b2 are the base lengths, h is the height

Filling in the given information, the area is ...

... A = (1/2)(73 ft +114 ft)(46 ft) = 4301 ft²

Since each square foot costs $0.23, this number of square feet will cost ...

... (4301 ft²)×$0.23/ft² = $989.23

The landscaper will charge $989.23 to put sod on the backyard.

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(i). \\ { \tt{area =  2(\frac{1}{2}  \times base \times height}} )\\  =   4 \times 3 \\  = 12 \: sq \: units \\  \\ (iii). \\  =  \frac{1}{2}  \times 8 \times  6 \\  = 24 \: sq \: units \\  \\ (ii). \\  =  \frac{1}{2}  \times 12 \times 5 \\  = 30 \: sq \: units

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