Narysuj trójkat ABC. Wykreśl figure symetryczna do tego trójkata względem punktu S leżacego:

Mathematics

1 answer:

wel4 years ago

4 0

Answer:

Unclear question. However, I infer you want a clear rendering of question.

Step-by-step explanation:

Draw an ABC triangle. Draw a figure symmetrical to this triangle with respect to the point S lying:

a) outside the triangle

b) on the vertex B of the triangle

c) inside the triangle

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What is the slope of this line?

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Answer:

$slope=\frac{1}{4}$

Step-by-step explanation:

The slope of a line can be seen as:

$\frac{rise}{run}$

Rise over run is the change in the y values over the change in x values. For example, in this graph, you would start on one of the points given. From there, you would move up first. After moving up a certain number of spaces, you would move to the side until you reach the other point.

In the graph, you would move up until you are in line with one of the other points. Starting at (-4,5), move up one space, then to the left 4 spaces to reach the point (0,6). Using the spaces moved in the rise over run:

$\frac{1}{4} =\frac{rise}{run}=slope$

Therefore, the slope is $\frac{1}{4}$ .

This is true for any two points on the line.

:Done

*When you move up, the number will be positive $(\frac{+y}{x} )$ . If you move down, the number will be negative $(\frac{-y}{x} )$ . If you move left, the number will be positive $(\frac{y}{+x})$ . If you move right, the number will be negative $(\frac{y}{-x} )$ . Keep this in mind. It is very important.