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zepelin [54]
3 years ago
10

How do you know if two line segments are perpendicular

Mathematics
2 answers:
avanturin [10]3 years ago
8 0

Answer:

You know if 2 line segments are perpendicular if they form a 90° angle.

It's like an L.

Vikki [24]3 years ago
5 0

Answer:

If they never cross/ intersect each other

Step-by-step explanation:

Answer

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Lane is 10 times Mels age.  If the difference in their age is 27, how old is Mel?
Sergeu [11.5K]
The answer is 3! 

explanation; 3x10 equals 30. the difference is 27 years and 30-3=27!
8 0
3 years ago
Read 2 more answers
Determine the quotient: (22.8 × 10–3) ÷ (5.7 × 10–6)
lana66690 [7]

Answer:

0.399

Step-by-step explanation:

The key to doing this problem properly lies in knowing and following order of operations rules.

Here we must perform mult. and div.  before  addition and subtr., but even before that we must do all work enclosed in parentheses first.

(22.8 × 10–3) is evaluated by doing the mult. first, and then subtracting 3:

(228-3) = 225

and

(5.7 × 10–6) is evaluated by doing the mult. first, then subtracting 6:

(570-6) = 564.

Finally, we divide 225 by 564, obtaining 0.399 (after rounding off to three decimal places).


8 0
3 years ago
Make a table for each function rule. Then graph each equation using the points you created.
aleksandrvk [35]

Answer:

1.f(x)=2x-5

i will take the set {-2,-1,0,1,2}

f(-2)=2(-2)-5

=-4-5

=-9

f(-1)=2(-1)-5

=-2-5

=-7

f(0)=2(0)-5

=-5

f(1)=2(1)-5

=-3

f(2)=2(2)-5

=-1

so the coordinates of the function is {-9,-7,-5,-3,-1}

2.f(x)=-3x+6

i will the take the set {-2,-1,0,1,2} too

f(-2)=-3(-2)+6=6+6=12

f(-1)=-3(-1)+6=3+6=9

f(0)=-3(0)+6=6

f(1)=-3(1)+6=-3+6=3

f(2)=-3(2)+6=-6+6=0

{12,9,6,3,0}

3.f(x)=2/3.x+4

{-2,-1,0,1,2}

f(-2)=2/3(-2)+4=-4/3+4=(-4+12)/3=8/3

f(-1)=2/3(-1)+4=-2/3+4=(-2+12)/3=10/3

f(0)=2/3(0)+4=4

f(1)=2/3(1)+4=2/3+4=(2+12)/3=14/3

f(2)=2/3(2)+4=4/3+4=(4+12)/3=16/3

{8/3,10/3,4,14/3,16/3}

you're can graph those coordinates

actually you can take other coordinates...

CMIIW

,

7 0
2 years ago
Which of the given expressions results in 0 when evaluated at x = 5? A. 5x(x − 7) B. (x − 8)(x − 5) C. (x + 7)(x − 2) D. (x + 5)
SSSSS [86.1K]

Answer:

B. (x - 8)(x - 5)

Step-by-step explanation:

If you plugged in x = 5 into the 2nd equation, you would see that you would be multiplying by 0, which would turn everything zero.

3 0
3 years ago
Read 2 more answers
Substitution again help please
Vesnalui [34]

Answer:

Step-by-step explanation:

1) 4x -3

x = -7 ;

4x - 3 = 4*(-7) - 3 = - 28 - 3 = -31

x = 14 ;

4x - 3 = 4*14 - 3 = 56 - 3 = 53

x = 0

4x - 3 = 0 - 3 = -3

2) 6 -3x

x = -7 ;

6 - 3x = 6 - 3*(-7) = 6 + 21 = 27

x = 14

6 - 3x = 6 - 3*14 = 6 - 42 = -36

x = 0

6 - 3x = 6 - 0 = 6

3) \dfrac{3x - 21}{7}\\\\x = -7\\\\\\\dfrac{3*(-7)-21}{7}=\dfrac{-21-21}{7}=\dfrac{-42}{7}=-6\\\\\\x = 14\\\\\dfrac{3*14-21}{7}=\dfrac{42-21}{7}=\dfrac{21}{7}=3\\\\\\x=0\\\\\dfrac{0-21}{7}=\dfrac{-21}{7}=-3\\\\

4)

\dfrac{3x}{7}-21\\\\\\x = -7\\\\\dfrac{3*(-7)}{7}-21=-3-21=-24\\\\\\x =14\\\\\dfrac{3*14}{7}-21=3*2-21=6-21=-15\\\\\\x=0\\\\\dfrac{0}{7}-21=-21

8 0
2 years ago
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