All categories

3 years ago

Can you help please help me with this question.

Mathematics

1 answer:

nasty-shy [4]3 years ago

4 0

Answer:

Step-by-step explanation:

Option A bcz a set should be well defined.

You might be interested in

Find the equation of the line that passes through the points 2,5 and -8,4

n200080 [17]

Answer:

y = 1/10 x + 24/5

or in standard form this is

-x + 10y = 48.

Step-by-step explanation:

The slope of the line is (5-4)/(2--8)

= 1/10

Using the point slope form y - y1 = m(x - x1):

USING THE POINT (2, 5):

y - 5 = 1/10(x - 2)

y - 5 = 1/10 x - 1/5

y = 1/10 x + 24/5

4 0

3 years ago

10) A 4 lb., 9 oz. Container of SpiceJungle Tandoori Spice cost $51.05. What is

mojhsa [17]

Answer:

give me a minute to find the answer

8 0

3 years ago

How much interest is earned on$2,700 in one year if it is invested at 3%

topjm [15]

Answer:81

Step-by-step explanation:

2700 x 0.03

3 0

3 years ago

Read 2 more answers

The radius of a circle is 4 feet. What is the area of a sector bounded by a 45° arc?

DIA [1.3K]

Answer:

$Area = 6.28\ ft^2$ or $Area = 2 \pi\ ft^2$

Step-by-step explanation:

Given

$Radius, r = 4ft$

$Angle, \theta = 45$

Required

Calculate the area of the sector

When angle is given in degrees, the area of sector is calculated as thus;

$Area = \frac{\theta}{360} * \pi * r^2$

$Substitute\ r = 4\ and\ \theta = 45$

$Area = \frac{\theta}{360} * \pi * r^2$ becomes

$Area = \frac{45}{360} * \pi * 4^2$

$Area = \frac{45}{360} * \pi * 16$

$Area = \frac{45*16}{360} * \pi$

$Area = \frac{720}{360} * \pi$

$Area = 2 * \pi$

$Area = 2 \pi\ ft^2$

The above is the area in terms of π

Solving further.... (Take π as 3.14)

$Area = 2 \pi\ ft^2$ becomes

$Area = 2 * 3.14\ ft^2$

$Area = 6.28\ ft^2$

Hence, the area of the sector is

$Area = 6.28\ ft^2$ or $Area = 2 \pi\ ft^2$

8 0

4 years ago

3. Find the domain and range of the function represented by the graph.

maks197457 [2]

The range is 1 to -3 (both included) and the domain is -3 to 2 (both included)

4 0

2 years ago