Write an equation perpendicular to y=-1/5x+9 that passes trough the point (-2,-2)
2 answers:
Answer: y=5x+8
Step-by-step explanation:
To find the perpendicular line, we know that the slope is the negative reciprocal of the equation. Therefore, we know that the slope will be 5. All we have to do is plug in the point to find the y-intercept.
[plug in (-2,-2)]
[multiply]
[add both sides by 10]
Now, we know the perpendicular equation is y=5x+8.
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Answer:
Step-by-step explanation:
area of the shaded region = Area of triangle formed in rectangle with base (10 - 6 = 4) 4m and height 2 m + Area of triangle formed in square with base 2 m and height 6 m
Refer the attached figure for the graphic representation of the given quadratic equation.
<u>Step-by-step explanation:</u>
Given expression:
To find:
The graphic representation of the given quadratic function
For solution, plot the graph to the given quadratic equation.
The standard form of the equation is
When comparing with given quadratic equation,
a = 1, b = - 8, c = 24
Axis of symmetry is
By applying the values, the axis of symmetry of given equation is
The vertex form of quadratic equation is
Where, (h,k) are the vertex.
Convert the quadratic equation into vertex form.
By completing the square,
On comparison,
(h , k) = (4 , 8)
Now, plot the equation with vertex (4,8) [refer attached figure].
