Question

Write an equation perpendicular to y=-1/5x+9 that passes trough the point (-2,-2)

Answer 1

Answer:

Y=5x + 8

Step-by-step explanation:

The slope of a perpendicular like would be 5

y = 5x + B

-2 = 5(-2)+ B

-2 = -10 + b

b = 8

Y=5x + 8

Answer 2

Answer: y=5x+8

Step-by-step explanation:

To find the perpendicular line, we know that the slope is the negative reciprocal of the equation. Therefore, we know that the slope will be 5. All we have to do is plug in the point to find the y-intercept.

$y=5x+b$              [plug in (-2,-2)]

$-2=5(-2)+b$      [multiply]

$-2=-10+b$         [add both sides by 10]

$b=8$

Now, we know the perpendicular equation is y=5x+8.