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Tems11 [23]
3 years ago
13

Dx+hy=j   what does x=

Mathematics
2 answers:
IRINA_888 [86]3 years ago
8 0
dx+hy=j\\
\\
dx=j-hy\\
\\
\boxed{x=\frac{j-hy}{d}}
DerKrebs [107]3 years ago
3 0
dx+hy=j\\\\dx=j-hy\ /:d\ \ \ \ and\ \ \ \ d \neq 0\\\\x= \frac{j-hy}{d}
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I'm an integer. I am less than zero but greater than -13. When you subtract me from -11. The result is positive. What number am
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<u>Answer</u><u>: </u>

Required integer is -12.

Step-by-step explanation:

Given:

Required number is integer.

Required integer is less than zero

greater than -13.

When number is substracted from -11, result is positive.

To Find:

The integer=?

Solution:

Lets assume required integer = x

As Required integer is less than zero and greater than -13 ,  

-13 < x < 0     ------(1)

Also when number is subtracted from -11, result is positive.  

=>  -11 – x > 0

=> -11 > x   -------(2)  

So form 1 and 2  

-13 < x < -11 that is x is an integer which is less than -11 and greater than -13.  There is only one integer between -13 and -11 that is -12.

Hence required integer is -12.

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