Computing the limit directly:
Alternatively, you can recognize the limit as being equivalent the derivative of <em>f(x)</em> at <em>x</em> = 2, in which case differentiating and plugging in 2 gives
<em>f'(x)</em> = 2<em>x</em> + 1 => <em>f'</em> (2) = 5
Answer:
Step-by-step explanation:
Let's call y the number of patients treated each week
Let's call x the week number.
If the reduction in the number of patients each week is linear then the equation that models this situation will have the following form:
Where m is the slope of the equation and b is the intercept with the x-axis.
If we know two points on the line then we can find the values of m and b.
We know that During week 5 of flu season, the clinic saw 90 patients, then we have the point:
(5, 90)
We know that In week 10 of flu season, the clinic saw 60 patients, then we have the point:
(10, 60).
Then we can find m and b using the followings formulas:
and
In this case: and
Then:
And
Finally the function that shows the number of patients seen each week at the clinic is: