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Elina [12.6K]
3 years ago
12

Write an equivalent expression for –2x+7

Mathematics
1 answer:
kiruha [24]3 years ago
4 0

Step-by-step explanation:

This expression is in its simplest form.

We can only expand them:

-2x + 7 = 3x - 5x + 7

-2x + 7 = x - 3x + 9 - 2

-2x + 7 = -x - x + 3 + 4

....

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2 vertical buildings are 42 metres apart and the shorter building is 135m high. The angle of elevation from the top of the short
ipn [44]

Answer:

Step-by-step explanation:

base=42 m

height=h=?

base angle θ=60°

tan 60=h/42

h=42tan 60=42√3≈72.75 m

height of taller building=135+42√3 m≈135+72.75≈207.75 m≈208 m

6 0
2 years ago
2+2 pls help btw 4 .....
Vsevolod [243]

Answer:

is it 22.

Step-by-step explanation:

is it?

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3 years ago
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Find f(x) if it is known that f(x−2)=2x−4.
tigry1 [53]
F(x) = 2x
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3 0
3 years ago
Write your answer with no spaces and any fraction with “/“
Alona [7]

Answer:

y=\frac{1}{2}x-2

Step-by-step explanation:

Because of the slope, we would assume that it is 1/2 because when you use rise over run, the graph rises 1 unit up and shifts 2 units to the right.  The -2 is where the y-intercept is (0, -2) based on the picture seen above.  The slope is also positive where it is going up instead of going down.

6 0
3 years ago
Recall that a 6-bit string is a bit strings of length 6, and a bit string of weight 3, say, is one with exactly three 1's. How m
strojnjashka [21]

Answer:

1.. Total number of 6 bit strings is 64

2. Number of 6-bit strings with weight of 0 is 1

3. Number of 6-bit strings with weight of 1 is 6

4. Number of 6-bit strings with weight of 3 is 20

5. Number of 6-bit strings with weight of 5 is 6

6. Number of 6-bit strings with weight of 6 is 1

7. Number of 6-bit strings with weight of 7 is 0

Step-by-step explanation:

A bit string is a string that contains 0 and 1 only

1. Total number of 6 bit strings is 2^6 = 64

2. Number of 6 bit strings with weight 0 is 1

Explanation

Weight 0 means a string with no occurrence of 1

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 0 i.e. no occurrence of 1

6C0 = 6!/(6-0)!0!

6C0 = 6!/6!0!

6C0 = 1

Hence, the number of string with weight 0 (i.e. no occurrence of 1 ) is 1

3. Number of string with weight 1 is 6

Explanation

Weight 0 means a string with exactly 1 occurrence of '1'

Here, we are only interested in occurrence and not order of occurrence

We apply combination formula for this

nCr = n!/(n-r)!r!

n = 6 and r = 1

6C1 = 6!/(6-1)!1!

6C1 = 6!/5!1!

6C1 = 6

Hence, the number of string with weight 6

4. Number of string with weight 3 is 20

Explanation

n = 6 and r = 3

6C3 = 6!/(6-3)!3!

6C3 = 6!/3!3!

6C3 = 20

Hence, the number of string with weight 3 is 20

5. Number of string with weight 5 is 6

Explanation

n = 6 and r = 5

6C5 = 6!/(6-5)!5!

6C5 = 6!/1!5!

6C5 = 6

Hence, the number of string with weight 5 is 6

6. Number of string with weight 6 is 1

Explanation

n = 6 and r = 6

6C6 = 6!/(6-6)!6!

6C6 = 6!/0!6!

6C6 = 1

Hence, the number of string with weight 6 is 1

7. Number of string with weight 7 is 0

Weight of 7 means that a string that has 7 occurrence of 1

The total length of a 6 bit is 6

Since 6 is less than 7, there's no way a bit of weight 7 can occur.

So, the right answer for this is 0.

8 0
3 years ago
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