Amount owed at the end of 1 year is 3640
<h3><u>Solution:</u></h3>
Given that yoko borrows $3500.
Rate of interest charged is 4% compounded each year
Need to determine amount owed at the end of 1 year.
In our case
:
Borrowed Amount that is principal P = $3500
Rate of interest r = 4%
Duration = 1 year and as it is compounded yearly, number of times interest calculated in 1 year n = 1
<em><u>Formula for Amount of compounded yearly is as follows:</u></em>

Where "p" is the principal
"r" is the rate of interest
"n" is the number of years
Substituting the values in above formula we get


Hence amount owed at the end of 1 year is 3640
-180 is the answer
explanation: order of operations
Answer:
A
Step-by-step explanation:
The slope of a vertical line is undefined
The slope of a horizontal line is 0
Answer:
x = 24/5
Step-by-step explanation:
16+5x=40
5x=40-16
5x= 24
x= 24/5
Answer:
Step-by-step explanation:-227 is in The sequence
13,7,1,-5,-11,.....
First term=a=13
Common difference=d=7-13=-6
Checking if -227 is in The sequence
using the formula
Tn=a+dx(n-1)
-227=13+(-6)x(n-1)
-227=13-6n+6
collect like terms
6n=13+6+227
6n=246
Divide both sides by 6
6n/6=246/6
n=41
Therefore -227 is the 41ist term Of The sequence