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Elena L [17]
3 years ago
11

In the xy-coordinate plane shown below, point P has coordinates (8,-6). Which

Mathematics
1 answer:
allsm [11]3 years ago
3 0

The answer will be D

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Find an equation of the line that has the given slope and contains the given point. m=7/3 (1,6)
iris [78.8K]

The point-slope form:

y-y_1=m(x-x_1)

We have the point (1, 6) and the slope m = 7/3. Substitute:

y-6=\dfrac{7}{3}(x-1)      <em>use distributive property</em>

y-6=\dfrac{7}{3}x-\dfrac{7}{3}          <em>add 6 to both sides</em>

y=\dfrac{7}{3}x+\dfrac{11}{3}        <em>multiply both sides by 3</em>

3y=7x+11           <em>subtract 7x from both sides</em>

-7x+3y=11         <em>change the signs</em>

7x-3y=-11

Answer:

point-slope form: y-6=\dfrac{7}{3}(x-1)

slope-intercept form: y=\dfrac{7}{3}x+\dfrac{11}{3}

standard form: 7x-3y=-11

5 0
3 years ago
You are traveling to Japan and need Japanese Yen (JPY). How much JPY could you get for $100 USD if the exchange rate is USD/JPY
Vanyuwa [196]

Answer:

107.15

Step-by-step explanation:

100/.9333=107.15

3 0
3 years ago
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One household is to be selected at random from a town. ​ ​The probability that ​the household has a cat is 0.20.2 . ​ ​The proba
dimulka [17.4K]

Answer:

There is a 50% probability that the household has a dog, given that the household has a ​cat.

Step-by-step explanation:

We solve this problem building the Venn's diagram of these probabilities.

I am going to say that:

A is the probability that a household has a cat.

B is the probability that a household has a dog.

We have that:

A = a + (A \cap B)

In which a is the probability that a household has a cat but not a dog and A \cap B is the probability that a household has both a cat and a dog.

By the same logic, we have that:

B = b + (A \cap B)

The probability that the household has a cat or a dog is 0.5

a + b + (A \cap B) = 0.5

The probability that the household has a dog ​is 0.4

B = 0.4

B = b + (A \cap B)

b = 0.4 - (A \cap B)

The probability that ​the household has a cat is 0.2.

A = 0.2

A = a + (A \cap B)

a = 0.2 - (A \cap B)

So

a + b + (A \cap B) = 0.5

0.2 - (A \cap B) + 0.4 - (A \cap B) + (A \cap B) = 0.5

A \cap B = 0.1

What is ​the probability that the household has a dog, given that the household has a ​cat?

20% of the households have a cat, and 10% have both a cat and a dog. So

P = \frac{A \cap B}{A} = {0.1}{0.2} = 0.5

There is a 50% probability that the household has a dog, given that the household has a ​cat.

4 0
2 years ago
-13=m-7 how can i solve for m
mart [117]

Answer: m=-6

Step-by-step explanation:

Add 7 to the other side

5 0
2 years ago
What is the coefficients and Constants for 5x-10
Artist 52 [7]

Answer:

coefficient is 5 and

constant is -10

7 0
3 years ago
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