Answer: D
Step-by-step explanation: right on edge :)
Answer:
-<em>6</em>
Step-by-step explanation:
because it - + 18 + 17 + 19 + 20 answers
Answer:
(-1, 2) — derivative is zero
Step-by-step explanation:
A critical point of a function is a point at which the slope is <em>zero</em> or <em>undefined</em>. (The critical point must actually be in the domain of the function. Vertical asymptotes are <em>not</em> critical points.)
You find the answer by looking for points on the graph where a tangent to the function is horizontal or vertical.
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In the given graph, the curve approaches horizontal near the point (-1, 2), so it is reasonable to estimate that that point is a critical point.
The attached graph also shows the inverse function. That has a critical point at (2, -1), where the slope is undefined (a tangent to the graph is vertical).
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The graph of a circle or ellipse does not pass the vertical line test, so is not a function. However, the graph still has critical points where the tangents are vertical or horizontal. The second attachment shows those critical points.
Answer:
1. 5 less than three times a number, n?
=3n-5
2 . Y multipled by 3.2 and then 12 added to the product ?
=3.2y+12
3. Eight more than four times a number , n ?
=4n+8
4. 8(m+1) =8m+8
Answer:
c. 2; no
Step-by-step explanation:
The inner product is the sum of the products of corresponding vector components. It is a scalar value, not a vector value.
(3, 5)·(4, -2) = (3)(4) +(5)(-2) = 12 -10 = 2
When the inner product is non-zero, the vectors are not perpendicular. (The yes answers with a non-zero value can be rejected out of hand.)
The appropriate choice is ...
2; no