REVIEW: -. Find the zeros of the function: f(x)=-3x – 6

Mathematics

1 answer:

horrorfan [7]3 years ago

6 0

Answer:x=-2

Step-by-step explanation:

You want to set up the equal to zero

Then add six to both sides

Then divide by -3x

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At what point do the lines y= 2x + 3 and y = 5x - 9 intersect?

QveST [7]

Answer:

(4,11)

Step-by-step explanation:

y=2x+3

y=5x-9

the first equation is equal to the second equation so

2x+3=5x-9

put like terms together

2x-5x= -9-3

-3x= -12

divide both sides by -3

.•.x=4

now, use the value of x to find the value of y like this:

y=2x+3 (x=4)

y=2(4)+3

y=8+3

y=11

therefore, the two lines intersect at the point (4,11)

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Grade 7 math extra credit

Nonamiya [84]

2400 in prize money...

the first winner will receive 1/3 of the money..
1/3 * 2400 = 2400/3 = 800
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3 years ago

I don't know how to do this or what i'm doing plz help

mote1985 [20]

recalling that d = rt, distance = rate * time.

we know Hector is going at 12 mph, and he has already covered 18 miles, how long has he been biking already?

$\bf \begin{array}{ccll} miles&hours\\ \cline{1-2} 12&1\\ 18&x \end{array}\implies \cfrac{12}{18}=\cfrac{1}{x}\implies 12x=18\implies x=\cfrac{18}{12}\implies x=\cfrac{3}{2}$

so Hector has been biking for those 18 miles for 3/2 of an hour, namely and hour and a half already.

then Wanda kicks in, rolling like a lightning at 16mph.

let's say the "meet" at the same distance "d" at "t" hours after Wanda entered, so that means that Wanda has been traveling for "t" hours, but Hector has been traveling for "t + (3/2)" because he had been biking before Wanda.

the distance both have travelled is the same "d" miles, reason why they "meet", same distance.

$\bf \begin{array}{lcccl} &\stackrel{miles}{distance}&\stackrel{mph}{rate}&\stackrel{hours}{time}\\ \cline{2-4}&\\ Hector&d&12&t+\frac{3}{2}\\[1em] Wanda&d&16&t \end{array}\qquad \implies \begin{cases} \boxed{d}=(12)\left( t+\frac{3}{2} \right)\\[1em] d=(16)(t) \end{cases}$

$\bf \stackrel{\textit{substituting \underline{d} in the 2nd equation}}{\boxed{(12)\left( t+\frac{3}{2} \right)}=16t}\implies 12t+18=16t \\\\\\ 18=4t\implies \cfrac{18}{4}=t\implies \cfrac{9}{2}=t\implies \stackrel{\textit{four and a half hours}}{4\frac{1}{2}=t}$