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svet-max [94.6K]
3 years ago
9

If ^dec=^bec,wich is true by cpctc

Mathematics
1 answer:
lesya692 [45]3 years ago
7 0

Answer:

BE is congruent to ED

Step-by-step explanation:


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NEED HELP ASAP!! Is there enough information to prove that the triangles are congruent?
stepan [7]

Answer:

did you got the answer

Step-by-step explanation:

because I need it too

please help me out

I've checked out and its <em>AAA does not prove congruence. Triangles are not congruent. They are similar </em>

but am not sure

8 0
3 years ago
If f(5) = 12, f ' is continuous, and 7 f '(x) dx 5 = 16, what is the value of f(7)? f(7) =
olganol [36]

The value of function f(x) at x = 7 is f(7) = 28

For given question,

we have been given the value of function f(x) at x = 5.

f(5) = 12

We have been given that f'(x) is continuous on 5 and 7

Also, \int\limits^7_5 {f(x)} \, dx =16

We need to find the value of f(7)

Since ∀x, f'(x) = f'(x), f is a primitive function of f' .

And f ' is continuous

\Rightarrow \int\limits^7_5 {f(x)} \, dx =16\\\\\Rightarrow [f(x)]_5^7=16

⇒  [f(7) - f(5)] = 16

⇒ f(7) - 12 = 16

⇒ f(7) = 16 + 12

⇒ f(7) = 28

Therefore, the value of function f(x) at x = 7 is f(7) = 28

Learn more about the function here:

brainly.com/question/19508092

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3 0
2 years ago
I’m kinda slow plz help:))
nadezda [96]

Answer:

trapaziod

Step-by-step explanation:

tbh Idek im guessing im a lil slow too... haha

3 0
3 years ago
Eugene wants to buy jeans at a store that is giving $10 off everything. The tag on the jeans is marked 50% off. The original pri
Rama09 [41]
Hi there

Part a
49.98−49.98×0.5
=24.99

Part b
49.98−10
=39.98

Hope it helps
5 0
3 years ago
The probability that an egg on a production line is cracked is 0.01. Two eggs are selected at random
ser-zykov [4K]

Answer:

Probability that both eggs are cracked is 0.0001.

Step-by-step explanation:

We are given that the probability that an egg on a production line is cracked is 0.01.

Two eggs are selected at random  from the production line.

The above situation can be represented through binomial distribution;

P(X = r) = \binom{n}{r} \times p^{r} \times (1-p)^{n-r};x=0,1,2,3,.......

where, n = number trials (samples) taken = 2 eggs

            r = number of success = both eggs are cracked

            p = probability of success which in our question is probability that

                 an egg on a production line is cracked, i.e; p = 0.01

<u><em>Let X = Number of eggs on a production line that are cracked</em></u>

So, X ~ Binom(n = 2, p = 0.01)

Now, Probability that both eggs are cracked is given by = P(X = 2)

                P(X = 2) =  \binom{2}{2} \times 0.01^{2} \times (1-0.01)^{2-2}

                              =   1\times 0.01^{2} \times 0.99^{0}

                              =  0.0001

<em>Therefore, probability that both eggs are cracked is </em><em>0.0001</em><em>.</em>

6 0
4 years ago
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