Answer:
m∠1=80°
m∠2=112°
m∠3=131°
m∠4=80°
m∠5=37°
Step-by-step explanation:
First you have to find m∠2
To do that find m∠6 (I created this angle shown in pic below)
Find m∠6 by using the sum of all ∠'s in a Δ theorem
m∠6=180°-(63°+49°)
m∠6=68°
Now you can find m∠2 with the supplementary ∠'s theorem
m∠2=180°-68°
m∠2=112°
Then you find m∠5 using the sum of all ∠'s in a Δ theorem
m∠5=180°-(112°+31°)
m∠5=37°
Now you can find m∠1
m∠1=180°-(63°+37°)
m∠1=180°-100°=80°
m∠4 can easily be found too now:
m∠4=180°-(63°+37°)
m∠4=80°
m∠3=180°-49°
m∠3=131°
Answer:
t(h)= (h-200)/-4.9
The time to reach a height of 50 meters is 30.6 seconds
Step-by-step explanation:
To express t as a function of height (h) we must transform the equation below:
h=200-4.9t
h-200=-4.9t
(h-200)/-4.9=t
t(h)= (h-200)/-4.9
To find the time to reach a height of 50 meters, we must replace this value on the new equation:
t(h)=50-200/-4.9
t(h)= 30.612
The time to reach a height of 50 meters is 30.6 seconds
Align the horizontal edge of the protractor with the base of the triangle. Place the center point of the protractor on the vertex of the angle. Follow the side of the triangle until it reaches the angle measurement mark. Note the measurement.
