Answer:
Solving systems of equations with 3 variables is very similar to how we solve systems with two variables. When we had two variables we reduced the system down
to one with only one variable (by substitution or addition). With three variables
we will reduce the system down to one with two variables (usually by addition),
which we can then solve by either addition or substitution.
To reduce from three variables down to two it is very important to keep the work
organized. We will use addition with two equations to eliminate one variable.
This new equation we will call (A). Then we will use a different pair of equations
and use addition to eliminate the same variable. This second new equation we
will call (B). Once we have done this we will have two equations (A) and (B)
with the same two variables that we can solve using either method. This is shown
in the following examples.
Example 1.
3x +2y − z = − 1
− 2x − 2y +3z = 5 We will eliminate y using two different pairs of equations
5x +2y − z = 3
Step-by-step explanation:
Its 5 years
worth = 18000
depriciation per year= 3
in 5 year car value= 18000 minus 5×3000= 3000
Answer:
The diameter of the circle = 10 cm
The radius of the circle= 10/2= 5 cm
Step-by-step explanation:
Area of the circle = pi r^2
= pi 5^2
=3.14 *25
= 78.5 cm ^2
Answer:
$300
Step-by-step explanation:
y = 100x + 300
where X represents the amount of months.
Answer: $44.50 per hour
Step-by-step explanation:
so easy
6hrs=$267
divide by 6 on both sides
1hr=$44.50
