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katen-ka-za [31]
4 years ago
13

What is the value of the x variable in the solution to the following system of equations?

Mathematics
2 answers:
Tpy6a [65]4 years ago
8 0
For the first set of equations, the value of y in the solution is -2.
For the second set of equations, the value of x in the solution<span> cannot be solved because they have the same slope.
</span>solve x and y values.
For the third set of equations, the value of x in the solution<span> is 3.</span>
Ostrovityanka [42]4 years ago
3 0

Answer:

x=2

Step-by-step explanation:

we have

4x+2y=6 -----> equation A

x-y=3

Isolate the variable y

y=x-3 -----> equation B

Substitute the equation B in the equation A and solve for x

4x+2(x-3)=6

4x+2x-6=6

6x=12

x=2

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7<br> 7 6/7 - 3 1/10 =<br> 0/1
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0 = 0 < 3 1/

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is less than 7 is less than 7 6/

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70

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The calculator performs basic and advanced operations with fractions, expressions with fractions combined with integers, decimals, and mixed numbers. It also shows detailed step-by-step information about the fraction calculation procedure. Solve problems with two, three, or more fractions and numbers in one expression.

5 0
3 years ago
Hugo took these steps to solve the system of equations.
KengaRu [80]

Answer:

C

Step-by-step explanation:

4 0
3 years ago
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BRAINLIEST!!!!!!<br> !!!!!!!
Iteru [2.4K]

Answer:

3x/4 - 17

Step-by-step explanation:

8 0
3 years ago
Assume that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p. Use the
KiRa [710]

Answer:

395, 17.212

(360.576,429.424)

Step-by-step explanation:

Given that a procedure yields a binomial distribution with n trials and the probability of success for one trial is p.

Here n=1580and p =1/4 =0.25\\q = 0.75\\np = 395 and\\nq = 1185

Since np and nq are greater than 5 by rule of thumb we can approximate binomial to normal.

Mean = np = 395

Variance = npq = 395*0.75=296.25

Std dev = 17.212

Thus X no of successes is N(395, 17.212)

THe the minimum usual value mu minus 2 sigma and the maximum usual value mu plus 2 sigma would be

395-2(17.212), 395+2(17.212)\\= 360.576,429.424

8 0
3 years ago
Figure AFigure B
Solnce55 [7]

Using the given information, the area of figure B is 315 ft²

<h3>Calculating Area </h3>

From the question, we are to calculate the area of figure B

In the given diagram, figure B is made up of a triangle and a square

∴ Area of figure B = Area of triangle + Area of square

Area of triangle = \frac{1}{2} bh

Where b is the base

and h is the height

Area of square = l^{2}

Where l is the length of a side

In the diagram,

l = b = 15 \ ft

h =12 \ ft

∴ Area of figure B = (\frac{1}{2}\times 15 \times 12) + 15^{2}

∴ Area of figure B = (15×6) + 225

∴ Area of figure B = 90 + 225

∴ Area of figure B = 315 ft²

Hence, the area of figure B is 315 ft²

Learn more on Calculating area here: brainly.com/question/23990217

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6 0
2 years ago
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