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san4es73 [151]
3 years ago
12

Find the 44th percentile, P44, from the following data! pls help

Mathematics
1 answer:
irina [24]3 years ago
6 0

Answer:

P_{44} = 29.9

Step-by-step Explanation:

The 44th percentile, P_{44}, of the given data can be calculated using the kth formula for percentile given as:

i = \frac{k}{100}(n + 1)

where,

i = the ranking or the position of the percentile = ?

k = the percentile = 44

n = total number of the given data values = 23

Plug in the values into the formula to find "i"

i = \frac{44}{100}(23 + 1)

i = \frac{44}{100}(24)

i = \frac{1,056}{100}

i = 10.56

Since "I", 10.56, is not an integer, round the number down, and round it up to the nearest integer, then look for the position each occupy in the ordered data set, and find their average.

Thus,

i_{down} = 10.56 = 10

i_{up} = 10.56 = 11

The data occupying the 10th position on the data set = 28.7

11th = 31.1

P_{44} = \frac{28.7 + 31.1}{2} = \frac{59.8}{2}

P_{44} = 29.9

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Temka [501]

Answer:

a) 0.283  or 28.3%

b) 0.130 or 13%

c) 0.4 or 40%

d) 30.6 mm

Step-by-step explanation:

z-score of a single left atrial diameter value of healthy children can be calculated as:

z=\frac{X-M}{s} where

  • X is the left atrial diameter value we are looking for its z-score
  • M is the mean left atrial diameter of healthy children (26.7 mm)
  • s is the standard deviation (4.7 mm)

Then

a) proportion of healthy children who have left atrial diameters less than 24 mm

=P(z<z*) where z* is the z-score of 24 mm

z*=\frac{24-26.7}{4.7} ≈ −0.574

And P(z<−0.574)=0.283

b) proportion of healthy children who have left atrial diameters greater than 32 mm

= P(z>z*) = 1-P(z<z*) where z* is the z-score of 32 mm

z*=\frac{32-26.7}{4.7} ≈ 1.128

1-P(z<1.128)=0.8703=0.130

c) proportion of healthy children have left atrial diameters between 25 and 30 mm

=P(z(25)<z<z(30)) where z(25), z(30) are the z-scores of 25 and 30 mm

z(30)=\frac{30-26.7}{4.7} ≈ 0.702

z(25)=\frac{25-26.7}{4.7} ≈ −0.362

P(z<0.702)=0.7587

P(z<−0.362)=0.3587

Then P(z(25)<z<z(30)) =0.7587 - 0.3587 =0.4

d) to find the value for which only about 20% have a larger left atrial diameter, we assume

P(z>z*)=0.2 or 20% where z* is the z-score of the value we are looking for.

Then P(z<z*)=0.8 and z*=0.84. That is

0.84=\frac{X-26.7}{4.7}  solving this equation for X we get X=30.648

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3 years ago
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The answer is:  [A]:  " 2 × 3 × 5 × 7 " .
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210 = 70 * 3 ;

70 * 3 = 35 * 2 * 3 ;

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6 0
3 years ago
Read 2 more answers
Can someone help me please?
marishachu [46]
(6x + 30)+(2x+6)= 180
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8 0
3 years ago
4,284 passengers traveling by the intercity bus every day, the intercity bus operates 6 hours every day, find the number of pass
Lemur [1.5K]

Answer:

714

Step-by-step explanation:

So lets go over what we know.

The bus only goes for 6 hours each day.

So lets just think of a full day as 6 hours.

Each day(6 hours), 4284 passangers ride the bus.

To find passangers per hour, we must divide the total passangers by the total hours.

This is 4284(total passangers) divided by 6(total hours):

4284/6

=

714

So each hour, there are 714 passangers.

Hope this helps!

7 0
3 years ago
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