Y = xe^x
dy/dx(e^x x)=>use the product rule, d/dx(u v) = v*(du)/(dx)+u*(dv)/(dx), where u = e^x and v = x:
= e^x (d/dx(x))+x (d/dx(e^x))
y' = e^x x+ e^x
y'(0) = 1 => slope of the tangent
slope of the normal = -1
y - 0 = -1(x - 0)
y = -x => normal at origin
Answer:
Probability of a sample that contains exactly two defective parts is .0037 or .37%
Step-by-step explanation:
As we know if P is the probability of achieving k results in n trials then probability formula is P = 
In this formula n = number of trials
k = number of success
(n-k) = number of failures
p = probability of success in one trial
q = (1-p) = probability of failure in one trial
In this sum n = 5
k = 2
number failures (n-k) = (5-2) = 3
p = 2% which can be written as .02
q = 98% Which can be written as .98
Now putting these values in the formula
P = 
P = 
= 5×4×3×2×1/3×2×1×2×1
= 5×2 =10
P = 10×(.02)²×(.98)³
= .0037 or .37%
You can add 7+3 then add 9 ad you get 19