Answer: The two roots are x = 3/2 and x = -2
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Explanation:
You have the right idea so far. But the two numbers should be 3 and -4 since
The -1 being the coefficient of the x term.
This means you need to change the -3x and 4x to 3x and -4x respectively. The other inner boxes are correct.
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Refer to the diagram below to see one way to fill out the box method, and that helps determine the factorization.
If we place a 2x to the left of -2x^2, then we need an -x up top because 2x*(-x) = -2x^2
Then based on that outer 2x, we need a -2 up top over the -4x. That way we get 2x*(-2) = -4x
So we have the factor -x-2 along the top
The last thing missing is the -3 to the left of 3x. Note how -3*(-x) = 3x in the left corner and -3*(-2) = 6 in the lower right corner.
We have the factor 2x-3 along the left side.
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The two factors are (2x-3) and (-x-2) which leads to the factorization (x+3)(-x+2)
The last thing to do is set each factor equal to 0 and solve for x
- 2x-3 = 0 solves to x = 3/2 = 1.5
- -x-2 = 0 solves to x = -2
The two roots are x = 3/2 and x = -2
Answer:
y=-2/3x+6
Step-by-step explanation:
Graph it
Answer:
D. 6x + 3
Step-by-step explanation:
A perimeter is just the sum of all sides of a shape.
First, write an equation to add all sides of the triangle:
(x + 4) + (3x - 2) + (2x + 1)
What is inside the parentheses is all already simplified. Also, it is addition, so the order in which we add does not matter. So, we can now get rid of the parentheses and combine like terms:
x + 3x + 2x + 4 -2 + 1
6x + 3
And that's our final answer: 6x + 3
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Answer:
y-intercept = a +y^2/12 term in it.
Then for y=6, you have
.. 6^2/12 -x^2/b = 1
.. 2 = x^2/b
.. b = x^2/2
If your point is (2√3, 6), then this is
.. b = (2√3)^2/2 = 12/2 = 6
Then the hyperbola's equation is
.. y^2/12 -x^2/6 = 1 . . . . . . . . selection D
Step-by-step explanation:
![x= \sqrt[8]{y} \\ y = z^{16} ](https://tex.z-dn.net/?f=x%3D%20%5Csqrt%5B8%5D%7By%7D%0A%5C%5C%20y%20%3D%20z%5E%7B16%7D%0A%0A%20)
Plug "y" into the first equation.