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3 years ago

Find the value of x.

Mathematics

1 answer:

Reptile [31]3 years ago

8 0

Answer:

3°

Step-by-step explanation:

20x + 5 = 9x - 2 + 40

Exterior angle is equal to the sum of interior angles

20x + 5 = 9x + 38

11x = 33

x = 3

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Anyone know how to do this

Artist 52 [7]

Answer:

Look in explanation

Step-by-step explanation:

I will assume that you're trying to solve for "x".

For number 1: 49+(5x+1) is a supplementary angle(180 degrees) so you can subtract 180-49 to get 131.

Now, 131 = 5x+1

-1 -1

130 = 5x

/5 /5

Now, we isolate the x to get x=26.

Number 2: There is a supplementary angle as well so we can put 5x+12+6x+3=180.

Now, combine the like terms to get 11x+15=180 so we now isolate x.

-15 -15

11x=165

/11 /11

x=15

Now, try the rest and set the terms to 180.

5x+1+8+4x=180

2x+1+x-10=180

6+x+5x=180

x+2+153=180(This is similar to #1)

CHECK YOU ANSWERS BELOW AFTER YOU HAVE ATTEMPED THE REST OF THE PROBLEMS.

3. x=19

4. x=63

5. x=29

6. x=25

3 0

3 years ago

Solve the given triangles by finding the missing angle and other side lengths.

coldgirl [10]

Answer:

a ≈ 27.65; B = 28°; c ≈ 19.17
a ≈ 163.30; B = 120°; c ≈ 59.77
A = 13°; b ≈ 0.3874; c ≈ 1.3737

Step-by-step explanation:

As long as you're seeking outside help, the use of a suitable tool is appropriate. Many graphing calculators, apps, and web sites are available for solving triangles.

Here, you're given two angles and a side. The third angle is the difference from 180° of the sum of the other two. For example, in the first problem, ...

B = 180° -A -C = 28°

The missing sides are found using the law of sines. Since you are given a side, use that as the reference, and its opposite angle as the reference angle. Then you have ...

side = sin(opposite angle)×<em>((reference side)/sin(reference angle))</em>

Note that the factor in italics remains the same for both remaining sides.

In the first problem, this becomes ...

a = sin(112°)·14/sin(28°) ≈ 27.65

c = sin(40°)·14/sin(28°) ≈ 19.17

The remaining problems are worked in similar fashion.

_____

<em>Comment on triangle solutions</em>

These are straightforward because you're given two angles. If you're given two sides and an angle, the solution method varies depending on which angle you're given (opposite the long side, the short side, or the unknown side). In the last case, the law of cosines is involved. In the second case, there are likely two solutions. Once you have two angles, you can proceed as above.