One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle. Then the lines are parallel
<h3><u>Solution:</u></h3>
Given that, One of the same-side exterior angles formed by two lines and a transversal is equal to 1/6 of the right angle and is 11 times smaller than the other angle.
We have to prove that the lines are parallel.
If they are parallel, sum of the described angles should be equal to 180 as they are same side exterior angles.
Now, the 1st angle will be 1/6 of right angle is given as:

And now, 15 degrees is 11 times smaller than the other
Then other angle = 11 times of 15 degrees

Now, sum of angles = 15 + 165 = 180 degrees.
As we expected their sum is 180 degrees. So the lines are parallel.
Hence, the given lines are parallel
The red line is 180 degrees. So the arcs on top of the circle all equal up to 180 degrees. the number 72 doesn't really matter cause you're trying to find out the angle of DCE which is on the other side of the circle. So you gotta find the arc length of DE which is 68 because 180-112=68. So to find the angle, you have to divide the opposite arc length by two, which is 34.
ANSWER: A. 34. you're welcomee!!
Me too , please help I'm taking a Geometry common assessment
The monthly salary is 2730.00.
Since there are 12 months in a year, to find the annual salary, we multiply the monthly salary by 12 as follows:
Annual Salary = Monthly Salary x 12 = 2730.00 x 12 = 32760.00