Funtion ! in vertex form is given by
<span>f(x) = 4x^2 + 8x + 1</span> = 4(x^2 + 2x + 1/4) = 4(x^2 + 2x + 1 + 1/4 - 1) = 4(x + 1)^2 + 4(-3/4) = 4(x + 1)^2 - 3
Thus, the least minimun value is (-1, -3)
Also, the least minimum value of function 2 is (-1, 0)
Therefore, function 1 has the least minimum value at (-1, -3)
Answer:
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Step-by-step explanation:
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](https://tex.z-dn.net/?f=%5Bx%28x%E2%88%922%29%2B6%28x%E2%88%922%29%5D%28x%E2%88%923%29)
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<h3>Hope it is helpful....</h3>
Answer:
B. -t+8
Step-by-step explanation:
add t to -2t and add 3 and 5
Right isosceles, which has two sides the same length and one angle that measures 90 degrees.