Answer: AAS
Step-by-step explanation:
Step-by-step explanation:
By Law of Indices,
8^(-2) = 8^0 / 8^2
= 1 / 64.
Answer:
<em>1500(1.02)^x + 600x</em> is how much he has in savings at the end of x years where it be in the bank or elsewhere
Step-by-step explanation:
x is in years
Let's just think about the investment of 1500 in an account earning 2% per year.
Before the years even start, you are at 1500 ( present value).
The next year (year 1), it would be 1500*.02+1500=(1500)(1.02).
The next year (year 2), it would be 1500(1.02)(.02)+1500(1.02)=1500(1.02)(1.02).
We keep multiplying factors of (1.02) each time.
So for year x, you would have saved 1500(1.02)^x.
Now we are saving 50 cash per month. Per year this would be 12(50) since there are 12 months in a year. 12(50)=600.
So the first year you would have 600.
The second year you would have 600(2) or 1200.
The third year you would have 600(3) or 1800.
Let's put this together:
1500(1.02)^x + 600x
Answer:
lesser x is 1
greater x is 3
Step-by-step explanation:
Here, we want to solve the equation so as to get the bigger and the lesser x values
We proceed as follows;
x^2 -4x + 3 = 0
x^2 - x-3x + 3 = 0
x(x-1) -3(x-1) = 0
(x-3)(x-1) = 0
x = 3
or x = 1
Greater x is 3
lesser x is 1
=