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3 years ago

I need help plz help me with it

Mathematics

1 answer:

Sidana [21]3 years ago

7 0

I need more to answer that can you maybe zoom out

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If l parallel m find the value of x and y

Katarina [22]

Answer:

14. x = 16; y = 23

15. x = 9; y = 13

Step-by-step explanation:

14. (4x + 4) = (7x - 44) (alternate exterior angles are congruent)

4x + 4 = 7x - 44

Collect like terms

4x - 7x = -4 - 44

-3x = -48

Divide both sides by -3

x = -48/-3

x = 16

39° + (8y - 43)° = 180° (consecutive exterior angles are supplementary)

39 + 8y - 43 = 180

Add like terms

-4 + 8y = 180

Add 4 to both sides

8y = 180 + 4

8y = 184

Divide both sides by 8

y = 184/8

y = 23

15. (15x - 26)° = (12x + 1)° (alternate exterior angles are congruent)

15x - 26 = 12x + 1

Collect like terms

15x - 12x = 26 + 1

3x = 27

Divide both sides by 3

x = 27/3

x = 9

28° + (12x + 1)° + (4y - 9)° = 180° (sum of interior angles of ∆)

Plug in the value of x

28 + 12(9) + 1 + 4y - 9 = 180

28 + 108 + 1 + 4y - 9 = 180

Add like terms

128 + 4y = 180

Subtract 128 from each side of the equation

4y = 180 - 128

4y = 52

Divide both sides by 4

y = 52/4

y = 13

5 0

3 years ago

ishmal invested £3500 for 3 years at 2.5% per annum simple interest. Work out the total amount of interest Ishmal earned.

Jlenok [28]

Answer:

Interest Earned is $262.5

Step-by-step explanation:

Interest=PRT/100

When P=Principal, R=Rate, T=Time

Interest earn =( 3500 x 3 x 2.5)/ 100

I=$26,250 / 100

I=$262.5

6 0

3 years ago

Please solve this ..................

AlladinOne [14]

Answer:

Step-by-step explanation:

√20=√5*2*2

√20=2√5

4 0

3 years ago

There is a pond on my property that Wildlife and Fisheries stocks. From information provided to me, I can expect my fish populat

LenaWriter [7]

An exponential function can either represent growth or decay

The initial value is 200 and the growth factor is 1.190
The number of fish in the pond after 5 years is 436

<u>(a) The initial number of fish and the growth factor</u>

The function is given as:

$P(t) = 200 \times 2^{t/4}$

An exponential function is represented as:

$P(t) = ab^t$

Where

a represents the initial value
b represents the growth factor

So, by comparison: the initial value is 200

The growth factor is then calculated as:

$b = 2^{1/4}$

$b = 1.190$

Hence, the initial value is 200 and the growth factor is 1.190

<u>(b) The number of fish after 5 years</u>

This means that t = 5.

So, we have:

$P(t) = 200 \times 2^{t/4}$

$P(5) = 200 \times 2^{5/4}$

$P(5) = 200 \times 2^{1.125}$

$P(5) = 436$

Hence, the number of fish in the pond after 5 years is 436

Read more about exponential functions at:

brainly.com/question/11464095

8 0

3 years ago

Graph both functions to find the solution(s) to the system.

Sliva [168]

F(x) = -2x +1 ( slope = -2 y intecept is 1)

replace x with 0 and solve for y =-2(0)+1 = 1 ( 0,1)
replace x with 2 and solve for y: -2(2) +1 = -4+1 = -3 (2,-3)

plot those 2 coordinates and draw a line

this is the red line on the attached graph

do the same for the g(x) formula
blue curve on graph.

5 0

3 years ago