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sesenic [268]
4 years ago
15

After a rotation of 90° about the origin, the coordinates of the vertices of the image of a triangle are A'(6,3), B'(-2, 1)

Mathematics
1 answer:
topjm [15]4 years ago
3 0

Rotation 90° counterclockwise about the origin

The coordinates of the pre-image are A (3 , -6) , B (1 , 2) , C (7 , -1)

Rotation 90° clockwise about the origin

The coordinates of the pre-image are A (-3 , 6) , B (-1 , -2) , C (-7 , 1)

Step-by-step explanation:

Let us revise the rotation

1. If point (x , y) rotated about the origin by angle 90° counter-clockwise

  then its image is (-y , x)

2. If point (x , y) rotated about the origin by angle 90° clock wise

   then Its image is (y , -x)

The given is:

After a rotation of 90° about the origin, the coordinates of the vertices

of the image of a triangle are A' (6 , 3), B' (-2 , 1)  and C' (1 , 7)

We need to find the coordinates of the pre-image

There is no mention about the rotation counterclockwise or clockwise,

then we will do both

∵ The rotation is 90° counterclockwise about the origin

∵ Point A (x , y) and its image A' (-y , x)

∵ A' = (6 , 3)

∴ -y = 6 and x = 3

∵ -y = 6 ⇒ multiply both sides by -1

∴ y = -6

∴ Point A is (3 , -6)

∵ Point B (x , y) and its image B' (-y , x)

∵ B' = (-2 , 1)

∴ -y = -2 and x = 1

∵ -y = -2 ⇒ multiply both sides by -1

∴ y = 2

∴ Point B is (1 , 2)

∵ Point C (x , y) and its image C' (-y , x)

∵ C' = (1 , 7)

∴ -y = 1 and x = 7

∵ -y = 1 ⇒ multiply both sides by -1

∴ y = -1

∴ Point C is (7 , -1)

The coordinates of the pre-image are A (3 , -6) , B (1 , 2) , C (7 , -1)

∵ The rotation is 90° clockwise about the origin

∵ Point A (x , y) and its image A' (y , -x)

∵ A' = (6 , 3)

∴ y = 6 and -x = 3

∵ -x = 3 ⇒ multiply both sides by -1

∴ x = -3

∴ Point A is (-3 , 6)

∵ Point B (x , y) and its image B' (y , -x)

∵ B' = (-2 , 1)

∴ y = -2 and -x = 1

∵ -x = 1 ⇒ multiply both sides by -1

∴ x = -1

∴ Point B is (-1 , -2)

∵ Point C (x , y) and its image C' (y , -x)

∵ C' = (1 , 7)

∴ y = 1 and -x = 7

∵ -x = 7 ⇒ multiply both sides by -1

∴ x = -7

∴ Point C is (-7 , 1)

The coordinates of the pre-image are A (-3 , 6) , B (-1 , -2) , C (-7 , 1)

Learn more:

You can learn more about rotation in brainly.com/question/3779181

#LearnwithBrainly

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3 years ago
Mario Mario solving the equation shown which value of x will make the equation true?​
Nata [24]

ANSWER

C. 25

EXPLANATION

The given equation is

\frac{1}{5} (x + 20) =  - x + 14 +  \frac{4}{5} x

Multiply through by 5:

5 \times \frac{1}{5} (x + 20) =  - x \times 5 + 14 \times 5 +  \frac{4}{5} x \times 5

Simplify:

x + 20=  -5 x +70 + 4x

Group similar terms:

{x}  + 5x - 4x = 70 - 20

Combine like terms:

2x = 50

Divide through by 2

x = 25

The correct choice is C.

6 0
4 years ago
What is the result when 6x3 + 23x2 + 15x + 28 is divided by 2x + 7?<br> I need help please someone
dangina [55]

Answer:

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Step-by-step explanation:

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5 0
3 years ago
If a boy 5 feet tall casts a shadow 14 feet long, what will be the length of the shadow of a tree that is 25 feet high?
klemol [59]

Answer:

70 feet

Step-by-step explanation:

This problem can be answered by using proportions based on similar triangles.

Notice that a person and its shadow on the ground form a right angle (therefore they can be considered the two "legs" of a right angle triangle)

The same runs for the tree and its shadow.

Since the inclination of the rays of the sun are the same at the same time for both objects (the boy and the tree), their hypothenuses form the same angles with the ground and therefore belong to similar triangles.

We can create the following proportion to solve for the shadow of the tree (ST) using the information provided: the height of the boy (HB), the shadow of the boy (SB), and the height of the tree (HT)

\frac{SB}{HB} =\frac{ST}{HT}\\\frac{14}{5} =\frac{ST}{25}\\\frac{ST}{25}=\frac{14}{5} \\ST=\frac{14*25}{5}\\ST=70\,\,ft

6 0
4 years ago
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