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stiv31 [10]
2 years ago
14

Does someone mind helping me with this problem? Thank you!

Mathematics
2 answers:
Ahat [919]2 years ago
5 0

Answer:

1.4 my guyyyyyyyyyyyyyyy

inessss [21]2 years ago
4 0

Answer:

0.708

Step-by-step explanation:

Change the divisor 2.1 to a whole number by moving the decimal point 1 places to the right. Then move the decimal point in the dividend the same, 1 places to the right.

We then have the equations:

14.88 ÷ 21 = 0.708

and therefore:

1.488 ÷ 2.1 = 0.708

Both calculated to 3 decimal places.

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Can someone please help me find the area of some of these?
Setler79 [48]
Number 5. 7776 in squared
7 0
3 years ago
PLZ HELP I WILL GIVE BRIANLY!
kumpel [21]

Answer:36

Step-by-step explanation:

\frac{4}{7} =\frac{48\\}{84}

for every 7 students there are 4 girls, so for every 84 there must be 48

7*12=84

4*12=48

so, in all 84 students there are 48 girls

so amount of boys=84-48=36

there are 36 boys

8 0
2 years ago
A rule of thumb for estimating the size of a crowd is that 2 people take up
Leno4ka [110]

Answer:

120 people

Step-by-step explanation:

Length of dance floor = 30 ft

Width of dance floor = 20 ft

Given that 2 people will occupy 5 ft² of space, the number of people that will crowd the floor of the dance floor is calculated as follows:

= Area of dance floor ÷ 5 ft²

= (30*20) ÷ 5

= 600 ÷ 5

= 120.

120 people will crowd the dance floor.

8 0
3 years ago
Please help me with 10 and 11
Gelneren [198K]

Answer:

10. 2x+y

11. x^2-15x+3

Step-by-step explanation:

10. when u add 7x+3y and 4x+4y you will get 11x+7y. 13x+8y minus 11x+7y will be 2x+y

11. when u add 3x^2+7x+1 and x^2-x+1 u will get 4x^2+6x+2. 5x^2-9x+5 minus 4x^2+6x+2 will be x^2-15x+3

5 0
3 years ago
Can it be concluded that if there is a 50% chance of contracting a communicable disease through contact with an infected person,
crimeas [40]

Answer:

No it cannot be concluded.

Step-by-step explanation:

The probability of getting the disease in the first attempt is 50%

The probability of getting the disease in the second attempt is 50%

Thus the probability of getting the disease in either of the turns is 50%+50%=100% (which may seem to be true)

BUT

The probability of not  getting the disease in the first attempt is 50%

The probability of not getting the disease in the second attempt is 50%

Thus the probability of not getting the disease in either of the turns is 50%+50%=100% (which is also true for this case)

Thus the probability of getting the disease in either of the 2 contacts is still 50%

4 0
3 years ago
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