All categories

3 years ago

PLEASE HELP!!!!!

Mathematics

1 answer:

Sidana [21]3 years ago

3 0

Answer:

Part a) The distance on a map between Joseph's house and the airport is 2.53 inches

Part b) The distance on a map between the airport and the restaurant is 1.68 inches and the total distance on a map between Joseph's house and the restaurant is 4.21 inches

Step-by-step explanation:

Part a) The actual distance between Joseph's house and the airport is 24 miles. How far apart are Joseph's house and the airport on the map?

we know that

The scale of a map is 1 inch : 9.5 miles

using proportion

Find the distance on a map if the actual distance between Joseph's house and the airport is 24 miles

Let

x-----> the distance on a map

1/9.5=x/24

x=24/9.5=2.53 inches

Part b) Joseph traveled from his house to the airport. He then traveled another 16 miles past the airport to a restaurant. How many inches on the map represent this distance?

we know that

The scale of a map is 1 inch : 9.5 miles

using proportion

Find the distance on a map if the actual distance between airport to the restaurant is 16 miles

Let

x-----> the distance on a map

1/9.5=x/16

x=16/9.5=1.68 inches

The total distance on a map between Joseph's house and the restaurant is equal to

2.53 inches+1.68 inches=4.21 inches

You might be interested in

PLZ HELP ME GEOMETRY question is below

nadezda [96]

For ΔABD, it is given that side AB is congruent to side CB, that ∠ABD is congruent to ∠CBD. In order to invoke the SAS Postulate, the remaining side(s) fo the triangles must be shown to be congruent. Those sides are BD and BD.

The appropriate choice is ...

... b. BD ≅ BD

3 0

2 years ago

100 POINTS!!!!!!!

Fed [463]

Answer:

a,b,c

Step-by-step explanation:

divide first

5 0

3 years ago

Y≤2x−3 y< -\frac{3}{4}x+8 y<− 4 3 x+8

FinnZ [79.3K]

Answer: the answer is 2x-1

5 0

3 years ago

What is the length of AB ? Round to the nearest tenth.

Vinvika [58]

The only way you can find x here is to use a trig ratio. We have the reference angle of 75, CA is 10 which is the side adjacent to the reference angle, and we are looking for the hypotenuse. The ratio that relates the side adjacent to a reference angle to the hypotenuse is cosine. Therefore, $cos(75)= \frac{10}{x}$ . Solving for x we get $x= \frac{10}{cos(75)}$ . Do that on your calculator and find that the hypotenuse is 38.6 m long, last choice from above.

8 0

2 years ago

Read 2 more answers

Let f(x) = -3x³ + 4 and g(x) = -8x² + 2x. What is f(x) g(x)? ·

SashulF [63]

Answer:

${ \tt{f(x).g(x) = ( - 3 {x}^{2} + 4)( { - 8x }^{2} + 2x) }} \\ = { \tt{( - 3 \times - 8) {x}^{(2 + 2)} + (2 \times - 3) {x}^{(2 + 1)} + ( - 8 \times 4) {x}^{2} + (4 \times 2)x }} \\ = { \tt{24 {x}^{4} - 6 {x}^{3} - 32 {x}^{2} + 8x}}$

7 0

1 year ago