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garik1379 [7]
3 years ago
13

The 7 a.m. flight from Dallas to Chicago is on time 75% of the time. Fran created this spinner to simulate the scenario. A spinn

er with 4 equal sections. 3 sections are shaded. Fran spun the spinner three times to predict whether the flight will be on time or late next Monday, Tuesday, and Wednesday. How should she interpret this outcome of the three spins: shaded-shaded-unshaded? The flight will be late all three days. The flight will be on time all three days. The flight will be late on one of the three days. The flight will be on time on one of the three days.
Mathematics
1 answer:
Paha777 [63]3 years ago
8 0

Answer:

<em>CORRECT OPTION is (C) The flight will be late on one of the three days.</em>

<em></em>

Step-by-step explanation:

The 7am flight from Dallas to Chicago is on time 75% of the time.

A spinner with four sections was created by Fran to simulate this scenario.

Since the 4 sections were equal, it means each section was 25% of the spinner.

3 sections were shaded. That implies 25 × 3 = 75% of the spinner was shaded area.

This coincides with the 75% probability that the flight is on time on a given day.

In other words, if the spinner's pointer lands on shaded area, the flight will be on time. If the pointer lands on an unshaded portion, the flight will be late.

Now Fran spun the spinner 3 times so she has 3 outcomes. The outcomes are:

- Shaded   - Shaded   - Unshaded

<em>CORRECT OPTION is (C) The flight will be late on one of the three days.</em>

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Solve the question in the picture and write the correct answer​
zlopas [31]

Answer:

  36.24 cm²

Step-by-step explanation:

The shaded region is the inscribed circle in the isosceles triangle. In order to find its area, we need to know the radius of the circle.

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One way to find the radius of the circle is to make use of the Angle Bisector theorem. It tells us an angle bisector divides the sides of a triangle proportionately. In the attached figure, that means angle bisector CD divides segment AE in proportion to sides CA and CE.

<h3>Side Length</h3>

To make use of this theorem, we need to know the length of side CA. That is the hypotenuse of right triangle AEC, so can be found using the Pythagorean theorem. Isosceles triangle ABC is given as having height AE=10 and base BC = 12.

  CA² = CE² +AE²

  CA² = 6² +10² = 136 . . . . . . . CE is half the base length: 12/2 = 6

  CA = √136 = 2√34

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<h3>Radius</h3>

Now we can write the proportion using the angle bisector theorem.

  DE/CE = DA/CA

  r/6 = (10 -r)/(2√34)

  r√34 = 3(10 -r) . . . . . . . multiply by 6√34

  r(3 +√34) = 30

  r = 30/(3 +√34)

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<h3>Area</h3>

From this, we can find the area of the shaded circle to be ...

  A = πr² = (3.14)(30/(3 +√34))²

  = 3.14·900/(43 +6√34) ≈ 36.2374 . . . cm²

The area of the shaded region is about 36.24 cm².

_____

<em>Additional comment</em>

Using area considerations, the formula for the radius of the inscribed circle in an isosceles triangle with base 'b' and sides 'a' can be found to be ...

  r=\dfrac{b}{2}\sqrt{\dfrac{2a-b}{2a+b}}

For a=√136 and b=12, this becomes ...

  r=\dfrac{12}{2}\sqrt{\dfrac{2\sqrt{136}-12}{2\sqrt{136}+12}}=6\sqrt{\dfrac{(\sqrt{34}-3)^2}{34-9}}=1.2(\sqrt{34}-3)\approx3.39714

This is the same value we found above.

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Answer:

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