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3 years ago

If w||v, solve for x.

Mathematics

1 answer:

IgorC [24]3 years ago

7 0

The two angles are alternate exterior angles, so they have the same measure.

5x+42=8x-15
5x+57=8x
57=3x
x=19

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Solve For Q q/10=4 Please Answer This For Me. Thanks.

Maurinko [17]

$\frac{q}{10} = 4\\q = 4 * 10\\q = 40$

Answer: 40.

3 0

3 years ago

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Solve using double substitution y=x-7 y=-2x+8

Ivenika [448]

Answer:

(5, -2)

Step-by-step explanation:

x - 7 = -2x + 8

add 2x to both sides

x - 7 + 2x = -2x + 8 + 2x

3x - 7 = 8

Add 7 to both sides

3x - 7 + 7 = 8 + 7

3x = 15

x = 5

y = 5 - 7

y = -2

Solution (5, -2)

8 0

3 years ago

Solve the rational inequality 2(x-4)/x<-4?

IgorLugansk [536]

Answer:

It’s not the answer but it’s a guide and something to be mindful of...

Step-by-step explanation:

You have to determine the zeros of the rational inequality by setting each factor equal to zero then solving for x. Use the zeros as critical numbers to divide the number line into distinct intervals.

Hope this helps... bless your heart.

7 0

3 years ago

Solve for x in the equation x2 + 14x+17--96

Veseljchak [2.6K]

Answer:

Option B.

Step-by-step explanation:

If a quadratic equation is defined as $ax^2+bx+c=0$ , the by quadratic formula

$x=\dfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

Consider the given equation is

$x^2+14x+17=-96$

We need to find the value of x.

Add 96 on both sides.

$x^2+14x+17+96=-96+96$

$x^2+14x+113=0$

Here, a=1, b=14 and c=113. Using quadratic formula we get

$x=\dfrac{-14\pm \sqrt{14^2-4(1)(113)}}{2(1)}$

$x=\dfrac{-14\pm \sqrt{-256}}{2(1)}$

$x=\dfrac{-14\pm \sqrt{256}\sqrt{-1}}{2}$ $(\sqrt{-1}=i)$

$x=\dfrac{-14\pm 16i}{2}$

$x=-7\pm 8i$

The value of x are x=-7 + 8i and x=-7 - 8i.

Therefore, the correct option is B.

8 0

3 years ago

There are 3 times as many pears are oranges. If a group of children receive 5 oranges each,there will be no left over.If the sam

lozanna [386]

There are 15 oranges

Solution:

Let "x" be the number of oranges

Let "y" be the number of pears

Let "c" be the number of children

There are 3 times as many pears are oranges

Number of pears = 3 times the number of oranges

y = 3x -------- eqn 1

If a group of children receive 5 oranges each, there will be no left over

So, "c" children receives 5 oranges each, there will be no left over

number of oranges = 5(number of children)

x = 5c ------- eqn 2

If the same group of children receive 8 oranges each, there will be 21 pears left over

number of pears = 8 oranges(number of children) + 21

y = 8c + 21

Substitute eqn 1

3x = 8c + 21 ---- eqn 3

Substitute eqn 2

3(5c) = 8c + 21

15c - 8c = 21

7c = 21

c = 3

Substitute c = 3 in eqn 2

x = 5(3)

x = 15

Thus there are 15 oranges

6 0

3 years ago

Read 2 more answers