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Kazeer [188]
3 years ago
13

Solve using double substitution y=x-7 y=-2x+8

Mathematics
1 answer:
Ivenika [448]3 years ago
8 0

Answer:

(5, -2)

Step-by-step explanation:

x - 7 = -2x + 8

add 2x to both sides

x - 7 + 2x = -2x + 8 + 2x

3x - 7 = 8

Add 7 to both sides

3x - 7 + 7 = 8 + 7

3x = 15

3x = 15

x = 5

y = 5 - 7

y = -2


Solution (5, -2)

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Sarah bought a shirt on sale for $35. The original price of the shirt was three times that amount Sarah also bought a pair of sh
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Answer:

$245


Step-by-step explanation:

Orignal price for shirt was 105

Original price for shoe sizes was 140

105+140=245

4 0
4 years ago
There are 9 people going on a trip. They purchased coach tickets for $160, and first class tickets for $1180. The total budget t
Savatey [412]

Answer:

Step-by-step explanation:

Given

There are 9 people going on a trip

They purchased coach tickets =$160

first class tickets =$1180

total budget to spend = $4500

Let coach tickets=X

So first class tickets=9-x

160x+1180(9-x)=4500

160+10620-1180x=4500

160x-1180x=4500-10620

-1020x=-6120

X=6120/1020

X=6

So answer

Coach tickets=X=6

First class tickets=(9-x)

=3.

4 0
3 years ago
Which statements are true about reflections? Check all that apply
MrRa [10]

Answer: Reflection is the change in direction of a wavefront between two different media so that the wavefront returns into the medium from which it originated.

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Solve for x.<br> -x/3=2<br><br> x= -6<br> x= -1<br> x = 6
LenKa [72]

Answer:

x = -6

Step-by-step explanation:

Solve for x:

-x/3 = 2

Multiply both sides of -x/3 = 2 by -3:

(-3 (-x))/3 = -3×2

-3×(-1)/3 = (-3 (-1))/3:

(-3 (-1))/3 x = -3×2

(-3)/3 = (3 (-1))/3 = -1:

--1 x = -3×2

(-1)^2 = 1:

x = -3×2

-3×2 = -6:

Answer:  x = -6

6 0
3 years ago
Define table represents a group frequency discretion of the number of hours spent on the computer per week for 49 student. What
Scilla [17]

Observe the given data distribution table carefully.

The 5th class interval is given as,

14.0-17.4

The upper limit (UL) and lower limit (LL) of this interval are,

\begin{gathered} UL=17.4 \\ LL=14.0 \end{gathered}

Thus, the upper-class limit of this 5th class is 17.4.

6 0
1 year ago
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