Sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
As given,
Let a-d, a, a +d be three numbers
Sum =33
⇒a-d + a +a +d =33
⇒ a =11
Sum of cubes= 5049
⇒ (a-d)³ + a +(a +d)³ =5049
⇒ a³ -d³ -3a²d +3ad² + a³ +a³ +d³ +3a²d +3ad² =5049
⇒3a³ + 6ad² = 5049
⇒ d=± 4
Therefore, sum of three numbers is 33 and sum of their cubes is 5049 then three numbers are 7,11,15 or 15,11,7.
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I think the mean would be the best because the data distribution is neither the mean nor median
Divide 327 by 12 to get 27.25. Howard pays 27 dollars and 25 cents for each card.
Step-by-step explanation:
1965 round to the nearest tenth is 1970
Answer:
5x + 2 - 2(4x - 2)
Step-by-step explanation:
-2 x 4x= -8x
5x-8x=-3x
-2 x -2= 4
4+2=6
-3x+6
hope this helped ^ ^
