The volume of a cube with side length equal to x, is

,
thus, the volume of a cube shaped box, whose side length is (5a+4b) is :

,
The volume is already expressed in terms of a and b, but we can expand the expression

, as follows:
![(5a+4b)^{3} =(5a+4b)(5a+4b)^{2}= (5a+4b)[ (5a)^{2}+2(5a)(4b)+ (4b)^{2}]](https://tex.z-dn.net/?f=%285a%2B4b%29%5E%7B3%7D%20%3D%285a%2B4b%29%285a%2B4b%29%5E%7B2%7D%3D%20%285a%2B4b%29%5B%20%285a%29%5E%7B2%7D%2B2%285a%29%284b%29%2B%20%284b%29%5E%7B2%7D%5D)
![=(5a+4b)[ 25a^{2}+40ab+ 16b^{2}]](https://tex.z-dn.net/?f=%3D%285a%2B4b%29%5B%2025a%5E%7B2%7D%2B40ab%2B%2016b%5E%7B2%7D%5D)
![=(5a)[ 25a^{2}+40ab+ 16b^{2}]+(4b)[ 25a^{2}+40ab+ 16b^{2}]](https://tex.z-dn.net/?f=%3D%285a%29%5B%2025a%5E%7B2%7D%2B40ab%2B%2016b%5E%7B2%7D%5D%2B%284b%29%5B%2025a%5E%7B2%7D%2B40ab%2B%2016b%5E%7B2%7D%5D)


Answer:

,
or
S=3.79. subtract 2.8 from 6.59 to get s
Use the rules of indices
When they are dividing we subtract the exponents provided the bases are the same.
Since the bases are the same,
(2/3)^5 ÷ (2/3)¹
Will be
(2/3)^5-1
= (2/3)⁴
= 16/81
Hope this helps.
y = 20x
The graph passes through the origin , hence is of form
y = mx ( m is the slope )
to calculate m use the gradient formula
m = (y₂ - y₁ ) / (x₂ - x₁ )
with (x₁, y₁) = (2, 40) and (x₂, y₂) = (4, 80) ← 2 points on the graph
m =
=
= 20
y = 20x