Answer:
Step-by-step explanation:
y = 2x^2 - 12x +19 Put brackets around the 1st 2 terms. Take 2
y = 2(x^2 - 6x ) + 19 Take 1/2 of the 6 square it and add inside the brackets
y = 2(x^2 - 6 + (6/2)^2) +19 Subtract 2 *9 from the 19. Express 1st 3 terms as ( )^2
y = 2(x- 3)^2 + 19 - 18
y = 2(x - 3)^2 + 1
Answers
y intercept when x = 0 is y = 19
axis of symmetry x = 3
vertex: (3,1)
Graph
graph: red
axis of symmetry: blue
y intercept, vertex: green
Answer:
m∠JKP = 31.5°
Step-by-step explanation:
Incenter of a triangle is the point where all the bisectors of interior angles intersect each other.
JN is the angle bisector of ∠KJL.
Therefore, m∠KJN = m∠LJN
(7x - 6) = (5x + 4)
7x - 5x = 6 + 4
2x = 10
x = 5
m∠KJN = (7x - 6)
= 7(5) - 6
= 35 - 6
= 29°
In ΔKJN,
m∠JKN + m∠KNJ + m∠NJK = 180°
m∠JKN + 90° + 29° = 180°
m∠JKN = 180°- 119° = 61°
Since KO is the angle bisector of ∠JKN,
m∠JKP = 
= 
= 30.5°
Well there really wouldn't be a combo since everything is different so I'm saying nun? that's what I'm going with. ( If this is wrong correct me )
It is 29 I might be wrong though