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lana [24]
3 years ago
14

How do i simplify the expression 2(8w + 4)

Mathematics
1 answer:
exis [7]3 years ago
8 0
You should distribute the 2. So you end up with 16w+8.
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How to solve it using explicit formula
Hatshy [7]

Answer:

Step-by-step explanation:

For these we always want to see how much each term is decreasing by, this will tell us what kind of series  it is.

-40, -47, -54, -61

Each time it DECREASES by -7, so it is an arithmetic sequence

The explicit form is found with two parts.  the start and how much each term changes by.  The start is -40 and the change is -7, so the explicit formula is -40 - 7(n-1).  This is assuming the first term is a_1.  If you are starting with a_0 instead you want to make (n-1) be n.  so if a_0 = -40 then you have -40 - 7n but if -40 = a_1 then you have -40 - 7(n-1)

the next one has a "common difference" of 30.  so now if -8 is a_0 you have -8 + 30n but if -8 is a_1 then you have -8 + 30(n-1)

8 0
3 years ago
Tanner has 80$ in an savings account. The interest rate is 10% and is not compounded. How much interest will he earn in 1 year?
Verizon [17]

Answer:

$8

Step-by-step explanation:

The formula for simple interest is i = p*r*t, where r is the interest rate as a decimal fraction.

Here, i = $80*0.10*1 = $8

4 0
3 years ago
Suppose you have already been waiting for one hour for a taxi. what is the probability that one arrives within the next 10 minut
Alona [7]

The probability of one arrives within the next 10 minutes when he already been waiting for one jour for a taxi is,

 

P (X > 70 | X > 60) = P (X > 10) = 1 – P (X ≤ 10) = 1 – {1 – e ^ -((1 / 10) 10)} = e ^ -1

= 0.3679

 

The probability of one arrives within the next 10 minutes when he already been waiting for one hour for a taxi is 0.3679

3 0
3 years ago
A circle has centre (3,0) and radius 5. The line y = 2x + k intersects the circle in two points. Find the set
lara [203]

A circle with center (3,0) and radius 5 has equation

(x-3)^2+y^2=25 \iff x^2 + y^2- 6 x  = 16

If we substitute y=2x+k in this equation, we have

x^2+(2x+k)^2-6x=16 \iff 5x^2+(4k-6)x+k^2-16=0

This equation has two solutions (i.e. the line intersects the circle in two points) if and only if the determinant is greater than zero:

\Delta=b^2-4ac=(4k-6)^2-4\cdot 5\cdot (k^2-16)>0

The expression simplifies to

-4 (k^2 + 12 k - 89)>0 \iff k^2 + 12 k - 89

The solutions to the associated equation are

k^2 + 12 k - 89=0 \iff k=-6\pm 5\sqrt{5}

So, the parabola is negative between the two solutions:

-6-5\sqrt{5}

8 0
4 years ago
Each student in Ms. Clark's class is decorating a shirt for a school program
Gennadij [26K]
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5 0
3 years ago
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