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ANEK [815]
4 years ago
13

Inequalities

+ 1" align="absmiddle" class="latex-formula">
​

Mathematics
1 answer:
Artemon [7]4 years ago
6 0

This is how graph gonna look like

Slop 2/1----->>>up 2 right 1

Y intercept ------1 beginning point

Y< so Shade below

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13. Based on the pattern, what are the next two terms of the sequence?
Anastasy [175]

Answer:

C. 22, 27

Step-by-step explanation:

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3 years ago
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Ulleksa [173]

Answer:

2nd level = 5000

3rd level = 7500

4th level = 10000

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multiply 2500 x the level

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PLSSSSSS HELP PLS
andreev551 [17]

Answer:

  • <em><u>Given </u></em><em><u>,</u></em>

student's age = x years.

  • <em><u>Also </u></em><em><u>,</u></em>

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  • <em><u>And </u></em><em><u>,</u></em>

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\bold{(3x  +  10) - (2x + 6)} \\\bold{  =  > 3x + 10 - 2x - 6} \\  \bold{=  > x + 4}

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5 0
2 years ago
Resolver: -4 (2 - 8x) - 3 (7x + 2) = 4x - 4 + x + 8
allsm [11]

Answer:

The chosen topic is not meant for use with this type of problem. Try the examples below.

2x+1 ,  3x+9

x3+x2+1 ,  x2+2x−6

x4+x ,  −x+6

Step-by-step explanation:

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3 0
3 years ago
April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t
dusya [7]

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

8 0
3 years ago
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