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Mariana [72]
3 years ago
13

April shoots an arrow upward into the air at a speed of 32 feet per second from a platform that is 11 feet high. The height of t

he arrow is given by the function ​h(t)equalsminus16t squaredplus32tplus11​, where t is the time is seconds. What is the maximum height of the​ arrow?
Mathematics
1 answer:
dusya [7]3 years ago
8 0

Answer:

27 ft

the maximum height of the​ arrow is 27 ft

Step-by-step explanation:

Given;

The height of the arrow is given by the function;

h(t) = -16t^2 + 32t + 11

Maximum height is at point when dh(t)/dt = 0.

Differentiating h(t), we have;

dh/dt = -32t + 32 = 0

Solving for t;

-32t = -32

t = -32/-32 = 1

t = 1 (time at maximum height is t = 1)

Substituting t=1 into h(t), to determine the value of maximum height;

h(max)= -16(1^2) + 32(1) + 11

h(max) = 27 ft

the maximum height of the​ arrow is 27 ft.

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Answer:

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Step-by-step explanation:

→ Calculate time taken

16:43 - 14:56 = 1 hour and 47 minutes

→ Write the speed formula and make distance the subject

Speed = Distance ÷ Time ⇔ Distance = Speed × Time

→ Convert 1 hour and 47 minutes into decimal format

1.78333333 or  1\frac{47}{60}

→ Substitute values into formula

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Step-by-step explanation:

Given that the system is

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