3 years ago

Simplify (20a^5)(b^3)/(10a^9)(b^2)

Mathematics

1 answer:

vodomira [7]3 years ago

8 0

Answer: 2a^-4 * b^2

Step-by-step explanation:

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What is the value of f(3) when f(x) = 4x + 1

valentina_108 [34]

Here is the equation:

$f(x)=4x+1$

You need to find f(3). To do that, substitute all the x's with 3:

$f(x)=4x+1 \rightarrow f(3)=4\times3 + 1$

The first thing you need to do is multiply 4 by 3. Multiply:

$4 \times 3 = 12$

Here is your new equation:

$f(3)=12+1$

To get your answer, you need to add 12 and 1. Add:

$12+1 = 13$

That means:

$\bf f(3)=13$

<em>If you have any questions, feel free to ask in the comments! :)</em>

3 0

3 years ago

Read 2 more answers

Evaluate the Riemann sum for (x) = x3 − 6x, for 0 ≤ x ≤ 3 with six subintervals, taking the sample points, xi, to be the right e

DENIUS [597]

Hello,

Reminders:
$$\sum_{i=1}^{n} i= \dfrac{n(n+1)}{2}$


$
$$ \sum_{i=1}^{n} i^2= \dfrac{n(n+1)}{2}$

$
$$ \sum_{i=1}^{n} i^3= \dfrac{n^2(n+1)^2}{4} $
$

$n=6\\
x_{0}=0\\
x_{n}=3\\
\Delta= \dfrac{x_n-x_0}{n}=0.5\\

$
$x_{i} =0+\Delta*i= \frac{i}{2}$

$\sum_{i=1}^{n}\ \Delta*f(x_{i})=\sum_{i=1}^{6}\ \dfrac{i^3/8-6i}{2}$
$$= \dfrac{1}{2}\sum_{i=1}^{6} (\frac{i^3}{8} -6i)=\dfrac{1}{16}*\frac{(6*7)^2}{4}- \frac{9*7}{2}= -3.9575$

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