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3 years ago

Simplify (20a^5)(b^3)/(10a^9)(b^2)

Mathematics

1 answer:

vodomira [7]3 years ago

8 0

Answer: 2a^-4 * b^2

Step-by-step explanation:

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The length of a rectangle is three times the width. The area of the rectangle is 108 sq. inches what’s the triangles width?

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3 years ago

Read 2 more answers

Need help ASAP!!!!!!

Mnenie [13.5K]

Answer:

Mean = 2.95

Median = 3

Step-by-step explanation:

The mean of the number of visits of 40 adults to the gym is

$\dfrac{0\cdot 4+1\cdot 3+2\cdot 12+3\cdot 5+4\cdot 8+5\cdot 5+6\cdot 2+7\cdot 1}{40}=\\ \\=\dfrac{3+24+15+32+25+12+7}{40}=\dfrac{118}{40}=2.95$

The median of the data is the average number between 20th and 21th terms (because 40 is even number, so the middle term is the average between two middle terms).

20th term = 3 visits

21th term = 3 visits

Hence, median is 3 visits

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3 years ago

The sum of three consecutive terms in an arithmetic sequence is 27, and their product is 585. find the three terms.

sammy [17]

$\text{the three consecutive terms in an arithmetic sequence}\\a;\ a+d;\ a+2d\\\\\text{system of equals}\\\\ \left\{\begin{array}{ccc}a+a+d+a+2d=27\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}3a+3d=27&|:3\\a(a+d)(a+2d)=585\end{array}\right\\ \left\{\begin{array}{ccc}a+d=9&\to d=9-a\\a(a+d)(a+2d)=585\end{array}\right\\$
$\text{substitute to the second equation}\\\\a(a+9-a)(a+2(9-a))=585\\\\a(9)(a+18-2a)=585\\9a(18-a)=585\ \ \ |:9\\a(18-a)=65\\18a-a^2=65\ \ \ |\text{change the signs}\\a^2-18a=-65\\a^2-2a\cdot9=-65\ \ \ |+9^2\\\underbrace{a^2-2a\cdot9+9^2}_{(a-b)^2=a^2-2ab+b^2}=-65+9^2\\(a-9)^2=16\to a-9\pm\sqrt{16}\\a-9=-4\ \vee\ a-9=4\ \ \ |+9\\a=5\ \vee\ a=13\\\\d=9-5=4\ \vee\ d=9-13=-4$
$Answer:\ a=5;\ a+d=9; a+2d=13\ vee\ a=13;\ a+d=9;\ a+2d=5$

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3 years ago

What is one tenth of two hundred

matrenka [14]

First you have to convert 1/10 into a decimal:
1/10= 0.1
Multiply 0.1 by 200:
0.1x200=20
So, 20 is 1/10 of 200.

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3 years ago

Suppose that the lifetimes of TV tubes are normally distributed with a standard deviation of 1.1 years. Suppose also that exactl

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