5 is the least you need to find the fasted car
A = 1/2bh...multiply both sides by 2
2A = bh...divide both sides by b
(2A)/b = h
s = 1/2gt^2...multiply both sides by 2
2s = gt^2...divide both sides by t^2
(2s) / (t^2) = g
H = vt - 5t^2...add 5t^2 to both sides
H + 5t^2 = vt...divide both sides by t
(H + 5t^2) / t = v
Answer:
Therefore the required equation is C = $ 15p - 60
Step-by-step explanation:
i) the price per gallon of paint = $p
ii) promotion offering price per gallon = $(p-4)
iii) cost of 15 gallons at the rate of promotion offering, C = 15(p - 4) = 15p - 60
Therefore the required equation is C = $ 15p - 60
K=5
Explanation: you have to rearrange the terms to make the problem look easier to solve then you have you subtract 2 from both sides of the equation then once you get that you have to simplify your answer (combine like terms) then after you divide both sides by 2 and then you should get your answer which is 5 here is a picture of the steps if you don't get it Hope this helps!
Answer:
58 hours
Step-by-step explanation:
First week: 25 5/8 hours = 25 hrs 37 mins and 30 sec
Second weeK: 32 5/6 hrs = 32 hrs and 50 mins
To find the toal time in minutes
(37 + 50) mins = 1 hr 27 mins
Threfore, total number of hours he worked in two weeks:
(25 + 32 + 1) hrs = 58 hours