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Fittoniya [83]
3 years ago
7

If a spacecraft was parked on Venus and needed to make a flight to Jupiter, how far would it need to travel?

Mathematics
1 answer:
Kryger [21]3 years ago
6 0
<span>The distance varies between 670.1 million kilometers at their closest and 1172.7 million kilometers at their farthest.</span>
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Solve for x: |4x + 12| = 16
frosja888 [35]
<span>|4x + 12| = 16
As it is in modulus function, it could be either +ve or -ve
4x+12 = 16   OR   4x - 12 = 16
4x = 16-12    OR   4x = 16 + 12
4x = 4           OR   4x = 28
x = 4/4     OR  x = 28/4
x = 1  OR   x = 7

In short, Your Answer would be either 1 or 7

Hope this helps!</span>
3 0
3 years ago
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Find the y-intercept of the line on the graph
Kitty [74]
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7 0
3 years ago
4x - 17 = 32 what is x
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6 0
3 years ago
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POSSIBLE POINTS
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4 0
3 years ago
Chen writes down a two digit number. He finds out that if he swapped the numbers, it would be three more than the 1/3 of the ori
inna [77]

Answer:

Step-by-step explanation:

From the information given,

Let the two digits that Chen writes down to be p and q

where,

q will be in the unit place and p will be in the tens place.

So, the value of the digit = 10p + q

So, if he swapped the number, he will have 10q + p

However,

the new number determined is thrice more than the 1/3 pf the original number.

i.e

the 1/3rd of the original number = \dfrac{1}{3}(10p+q)

=\dfrac{10p+q}{3}

thrice more than that will be = \dfrac{10p+q}{3} + 3

∴

\dfrac{10p+q}{3} + 3 = 10q+p

multiply through by 3, we have :

10p+q + 9 = 30q + 3p

collecting the like terms, we have:

10p - 3p +q -30q +9 = 0

7p - 29q +9 = 0

7p - 29q = -9

Therefore, p,q lie between 0 and 9

Therefore, the possibility of the original number is p = 7 and q = 2

8 0
3 years ago
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