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Pavel [41]
3 years ago
7

What angle has no supplement

Mathematics
2 answers:
monitta3 years ago
8 0
Supplementary add up to 180 degrees (140° and 40°)
Complementary add up to 90 degrees
jasenka [17]3 years ago
5 0
Supplement is te angle that ads to 180
maybe the angle that is more than 180 (you can't have negative angles)
or maybe it is 180, since it is alreay equal to 180
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HELPPPP!!!!!!!!!!!!!
juin [17]
I think its C Because Aob is a given angle Boc is where we prove Aob so Im 95% sure its c
4 0
2 years ago
A sporting goods store has a sale on soccer balls: if you buy two soccer balls at the regular price, you get a third soccer ball
Snowcat [4.5K]

Answer:

The regular price of the balls is $8

Step-by-step explanation:

The sporting goods store sales promotion is as follows;

The price of the third ball after buying two balls at regular price = $1.00

The price of the number of balls Coach John pays for the balls he bought = $136

To buy 24 balls, we have;

2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1 + 2 + 1

Therefore;

The number of balls bought at regular price = The sum of the 2s = 16 balls

The number of balls bought for $1 = 24 - 16 = 8 balls

Let x represent the regular price of the balls, we have;

16 × x + 8 = 136

16·x = 138 - 8 = 128

x = 128/16 = 8

The regular price of the balls = x = $8.

7 0
3 years ago
Some one plz tell me how to do this
goldenfox [79]
Subtract the 18 from the 78 then multiply both sides by -1, then divide by 5.
8 0
3 years ago
Read 2 more answers
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laila [671]

Answer:

8+7r+2q

Is the required answer.

7 0
3 years ago
If m and n are the zeroes of the polynomial 6y 2 -7y – 2, find a polynomial whose zeroes are 1/m and 1/n
denis-greek [22]

Answer:

y^2-\frac{7}{2}y+3

Step-by-step explanation:

Given polynomial is,

6y² - 7y - 2

Fro the zeros of the given polynomial,

6y² - 7y - 2 = 0

6y² - 4y - 3y - 2 = 0

2y(3y - 2) - 1(3y - 2) = 0

(2y - 1)(3y - 2) = 0

(2y - 1) = 0

y = \frac{1}{2}

(3y - 2) = 0

y = \frac{2}{3}

Therefore, zeros of this polynomial are m = \frac{1}{2} and n = \frac{2}{3}

If a polynomial has zeros as \frac{1}{m} and \frac{1}{n} then the zeros will be \frac{3}{2} and 2.

Polynomial will be,

(y-\frac{3}{2})(y-2)

= y(y-2)-\frac{3}{2}(y-2)

= y^2-2y-\frac{3}{2}y+3

= y^2-\frac{7}{2}y+3

7 0
3 years ago
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