Answer:
Solution given;
A(x1,y1)=(7,4)
B(x2,y2)=(-8,4)
distance AB=?
we have
d=
AB=
AB=15 units
the distance between the two points is 15 units.
Show that det(A) = 0 without directly evaluating the determinant. A = [-4 1 1 1 1; 1 -4 1 1 1; 1 1 -4 1 1; 1 1 1 -4 1; 1 1 1 1 -
2 answers:
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Refer to the attached image. Since one vertex is the origin and the other two lay on the coordinate axes, the triangle is a right triangle. This means that, if we consider AB to the be base, AC is his height, and vice versa.
Anyway, it means that the area is given by
Since AB is a horizontal segment and AC is a vertical segment, their length is given by the absolute difference of the non-constant coordinate: points A and B share the same x coordinate, so we subtract the y coordinates:
The opposite goes for AC: points A and C share the same y coordinate, so we subtract the x coordinates:
So, the area is
